Weird way to write it but alright! (Sideways)
19pq^-2 x 5pq^6 = ?
These problems are pretty much single operations between each of the variables / constants.
So it's like this:
(19*5)(p*p)(q^-2*q^6) = ?
19*5 is 95.
For p*p remember that when two variables multiply there given powers add. In the case where the powers are not shown (like in the case of p*p) they are always assumed to be 1. So what is 1+1? 2.
p*p is p^2
For q^-2*q^6 it is the same deal with the previous problem. So now the problem looks like this:
-2 + 6 = 4
(The two is negative, because the power is negative 2)
So, q^4.
Our final answer is all of the combined.... like a so:
95p^2q^4
Answer:
See below
Step-by-step explanation:
Do you mean -12(x+5)=-10?
Divide both sides by -12 -> x+5=10/12
Subtract 5 on both sides -> x=10/12-5 -> x=-4 1/6
So x=-4 1/6
Let me know if this wasn't the right equation
Hey there! :)
Answer:
(2, -2)
Step-by-step explanation:
-2x + y = -6
4x + 3y = 2
We can begin by setting the first equation equal to y:
-2x + y = -6
Add 2x to both sides:
y = 2x - 6
Plug this equation for y into the second equation:
4x + 3(2x - 6) = 2
Distribute:
4x + 6x - 18 = 2
Combine like terms:
10x = 20
x = 2
Plug the value of 'x' into an equation to solve for 'y':
-2(2) + y = -6
-4 + y = -6
y = -2
Therefore, the solution is (2, -2)
The value would be 4.
First, you have to do 4 + 3 because it's in parenteces. This equals 7
Secondly, you have to do 2 x 7, which is 14.
Last you have to do 18 - 14 which is 4.
