Can someone please answer my last post? (its calculus)
1 answer:
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Answer:
see attachment for graph
Step-by-step explanation:
< or > : dashed line
≤ or ≥ : solid line
< or ≤ : shade below the line
> or ≥ : shade above the line
<u>To graph the line y < 3x-2</u>
Rewrite the equation as: y = 3x - 2
Find two points on the line:
when x = 0, y = 3(0) - 2 = -2 → (0, -2)
when x = 3, y = 3(3) - 2 = 7 → (3, 7)
Plots the found points (0, -2) and (3, 7).
Draw a straight, dashed line through the points.
<u>To graph the line y ≥ -x + 3</u>
Rewrite the equation as: y = -x + 3
Find two points on the line:
when x = 0, y = -(0) + 3 = 3 → (0, 3)
when x = 3, y = -(3) + 3 = 0 → (3, 0)
Plots the found points (0, 3) and (3, 0).
Draw a straight, solid line through the points.
Shade above the solid line and below the dashed line to the right of where the two lines intersect. <u>The shaded area is the area of all possible solutions</u>.
