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andrew-mc [135]
3 years ago
13

Please help! I will mark brainliest!

Mathematics
1 answer:
Maurinko [17]3 years ago
4 0

\left(3.5\times 10^{-2}\dfrac{kg}{L}\right)\times\left(2.64\times 10^{20}\,L\right)=(3.5\times 2.64)\times 10^{(-2+20)}\,kg\\\\=\bf{9.24\times 10^{18}\,kg}

_____

Multiply the numbers and add the exponents.

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<em>Answer</em><em> </em><em>is</em><em> </em>

<em>There</em><em> </em><em>are</em><em> </em><em>53</em><em> </em><em>terms</em><em> </em><em>in</em><em> </em><em>sequence</em><em> </em><em>.</em>

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<em>the \: given \: sequence \: is \\  4[tex]the \: given \: sequence \: is \\  4,9[tex]the \: given \: sequence \: is \\  4,9,14.......264 \\ to \: find \: the \: no.of \: terms \: we \: have \: the \: formula \\ n =  \frac{l - a}{d}  + 1 \\  here \: l = 264 \:  \:  \: a = 4 \:  \:  \ \\ d = t2 - t1 = 9 - 4 = 5 \:  \: d = 5 \\ on \: substituting \: the \: values \: in \: the \: formula \\ n =  \frac{264 - 4}{5}  + 1 \\  =  \frac{260}{5}  + 1 \\  = 52 + 1 \\  = 53 \: terms[tex]the \: given \: sequence \: is \\  4,9,14.......264 \\ to \: find \: the \: no.of \: terms \: we \: have \: the \: formula \\ n =  \frac{l - a}{d}  + 1 \\  here \: l = 264 \:  \:  \: a = 4 \:  \:  \ \\ d = t2 - t1 = 9 - 4 = 5 \:  \: d = 5 \\ on \: substituting \: the \: values \: in \: the \: formula \\ n =  \frac{264 - 4}{5}  + 1 \\  =  \frac{260}{5}  + 1 \\  = 52 + 1 \\  = 53 \: terms</em>

<em>HAVE A NICE DAY</em><em>!</em>

<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>

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