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Usimov [2.4K]
3 years ago
9

what number should be added to the expression x^2 + 10x to change it into a perfect square trinomial?​

Mathematics
2 answers:
Tamiku [17]3 years ago
6 0

Answer:

25

Step-by-step explanation:

In case anyone was confused the answer is 25. took the test.

Annette [7]3 years ago
3 0

Answer:

\large\boxed{5^2=25}

Step-by-step explanation:

\text{Perfect square:}\ (a+b)^2=a^2+2ab+b^2\\\\x^2+10x\\\Downarrow\\x^2+2(x)(5)\\\Downarrow\\x^2+2(x)(5)+5^2=(x+5)^2

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goblinko [34]

Answer:

The correct option is C : x² + (y +3)² = 9 .

Step-by-step explanation:

We know that the general equation for a circle is ( x - h )² + ( y -k )²= r², Where,

  • r is the radius.
  • (h , k) is the center.

Let the point be ( 0 , -y) , since it is on negative y axis . And the circle passes through the origin that is (0,0) . Hence the center will be 3 units down the y - axis that is ( 0 , -3) .Hence h will be 0 and y = (-3) .

Now its given that the radius of the circle is 3. So on substituting r = 3 , in standard form we have ,

⇒ ( x -h )² + ( y - k )²= r²

⇒ ( x - 0)² + { y - (-3) }² = 3²

⇒ x² + ( y + 3) ² = 3²

⇒ x² + ( y + 3)² = 9

<h3><u>Hence </u><u>the</u><u> </u><u>corre</u><u>ct</u><u> </u><u>option</u><u> </u><u>is</u><u> </u><u>C</u><u> </u><u>[</u><u> </u><u>x²</u><u> </u><u>+</u><u> </u><u>(</u><u> </u><u>y</u><u>+</u><u>3</u><u>)</u><u>²</u><u> </u><u>=</u><u> </u><u>9</u><u> </u><u>]</u><u> </u><u>.</u></h3>

Note that I have attached the graph of the same .

3 0
3 years ago
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