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Alla [95]
3 years ago
6

The grass on Julie's lawn was 4.5 centimeters tall right after she mowed it. Then the grass

Mathematics
1 answer:
telo118 [61]3 years ago
4 0

Answer:    w = 2.1h + 4.5

Step-by-step explanation:

w is the number of weeks since Julie mowed the lawn

h is the height of the grass

w=the rate the grass grew at and the grass on Julies lawn

w=2.1h+4.5

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A researcher took a poll of people in his state. He asked each person if he or she had any pets (Yes or No) and to state his or
Arlecino [84]

Answer:

DF = 2

Step-by-step explanation:

Formula for degree of freedom is;

DF = n - 1

Where n is sample size

In this question, political party affiliation could be Republican, Democrat, or Other. Thus, sample size is 3.

DF = 3 - 1

DF = 2

Thus, degree of freedom value would be 2

8 0
3 years ago
with reference to a universal set, the inclusion of a subset in another is relation which is a) symmetric only b) transitive onl
Vlad [161]

Answer:

D?

Step-by-step explanation:

I think it is D since a universal set would only be {1,2,3,4,5,6,...} and the subset would not satisfy any of the conditions of symmetric, transitive, and reflexive.

5 0
3 years ago
Grace deposits $1000 in a mutual fund earning 9.5% annual interest, compounded monthly. Write an exponential function that model
olya-2409 [2.1K]
See the attachment for the answer and enjoy :)
add this statement at the end...... "<span>Also, if she retires at 67, then there are 67-25=42 years of investment, which gives A=$53212.28"</span>

4 0
3 years ago
How do you solve x+4=10^x
raketka [301]
Two ways to solve the problem:

A. By graphing f(x)=10^x and g(x)=x+4.
The intersection(s) will be the solution.
See graph below, approximate solutions: (-4,0),(0.66, 4.67)

B. Refine approximate solutions using Newton's method
Let h(x)=f(x)-g(x) = 10^x-x-4 ...............(1)
we calculate the derivative, h'(x) = log(10)*10^x-1   [ note:log(x) means ln(x) ]
and use Newton's iterative formula to find successive approximations to the root, basically refining the approximate solutions.
The iterative formula for nth approximation x_n is given by
x_n = x_{n-1} - h(x_n) / h'(x_n)....(2)

Using initial approximation (-4,0), we have x0=-4
x1
=x0-h(x0)/h'(x0)
=-4 - h(-4)/h'(-4)
=-4 - (10^(-4)-(-4)-4)/(log(10*10^(-4)-1)
=-4 - (1/10000)/(log(10)/10000-1)
=-3.9999000

Repeating the same for second approximation, x2, we get
x2=-3.99989997696619 which is accurate to 14 places after decimal

Now we can refine the other approximate solution, x0=0.66 to find
x1=0.669356
x2=0.6692468481102326
x3=0.669246832877748
x4=0.6692468328777476
So we will accept x=0.669246832877748

So the solutions are S={-3.99989997696619,0.6692468328777476}  both accurate to 14 places after the decimal

3 0
3 years ago
What is the answer to find f(-2) for
Oksi-84 [34.3K]

Answer:

Pretty sure you have to find the constant be tween -2x. and f(x) divided by -4

Step-by-step explanation:

5 0
3 years ago
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