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1) 9m
2) 1/64
3) 50d^3
4) pq^2 (p-q) (p-q)
= pq^2 ( p^2 - 9p -9p +18)
= pq^4 - 18p^2q^2 + 8pq^2
= q^2 - 18p + 8
*assuming that ABC is a straight line**
<span>then you have </span>
<span>AB = 17.89 ..... this is the length of the whole line </span>
<span>BC is a part of the line = 7 </span>
<span>therefore the length of the other part = 17.89 - 7 </span>
<span>= 10.89</span>
Recall that the area of a circle can be determined by the formula pi * r(squared). Since we are given the diameter, we can divide it by 2, giving us the radius. 10 / 2 = 5 Now that we have all of our values, we substitute them into the formula for area. 3.14 * 5(squared) This simplifies to 3.14 * 25 Which gives us 78.5 I hope that helps.
