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3 years ago

Elizabeth rolls a die 108 times. How many times can she expect to roll a 2? A. 54 B. 18 C. 36 D. 24

Mathematics

2 answers:

gregori [183]3 years ago

6 0

As there are 6 numbers on a die you would expect to 2 roll about 108/6 = 18 times

B

Gala2k [10]3 years ago

5 0

Answer is B. 54 times

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Determine which system will produce indefinite many solutions

Vinvika [58]

Answer:

Where are the systems?

Step-by-step explanation:

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3 years ago

I paid $8.50 each for movie tickets and i spend a total of $144.50. If n, represents how many tickets i bought, write and equati

damaskus [11]

Answer:
$144.50/8.50 = n

Explanation:
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2 years ago

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Which of the following best describes the solution to the system of equations below?

OverLord2011 [107]

Answer: OPTION A

Step-by-step explanation:

The equation of the line in slope-intercept form is:

$y=mx+b$

Where m is the slope and b the y-intercept.

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$\left \{ {{5y=-4x+7} \atop {10y=-8x+14}} \right.\\\\\left \{ {{y=\frac{-4}{5}x+\frac{7}{5}} \atop {y=\frac{-8}{10}x+\frac{14}{10}}} \right.\\\\\left \{ {{y=\frac{-4}{5}x+\frac{7}{5}} \atop {y=\frac{-4}{5}x+\frac{7}{5}}} \right.$

As you can see the slope and the y-intercept of each equation are equal, this means that both are the exact same line. Therefore, you can conclude that the system has infinitely many solutions.

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3 years ago

What is the remainder when 599 is divided by 9?

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3 years ago

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An aeroplane X whose average speed is 50°km/hr leaves kano airport at 7.00am and travels for 2 hours on a bearing 050°. It then

Zigmanuir [339]

Answer:

(a)123 km/hr

(b)39 degrees

Step-by-step explanation:

Plane X with an average speed of 50km/hr travels for 2 hours from P (Kano Airport) to point Q in the diagram.

Distance = Speed X Time

Therefore: PQ =50km/hr X 2 hr =100 km

It moves from Point Q at 9.00 am and arrives at the airstrip A by 11.30am.

Distance, QA=50km/hr X 2.5 hr =125 km

Using alternate angles in the diagram:

$\angle Q=110^\circ$

(a)First, we calculate the distance traveled, PA by plane Y.

Using Cosine rule

$q^2=p^2+a^2-2pa\cos Q\\q^2=100^2+125^2-2(100)(125)\cos 110^\circ\\q^2=34175.50\\q=184.87$ km$

SInce aeroplane Y leaves kano airport at 10.00am and arrives at 11.30am

Time taken =1.5 hour

Therefore:

Average Speed of Y

$=184.87 \div 1.5\\=123.25$ km/hr\\\approx 123$ km/hr (correct to three significant figures)$

(b)Flight Direction of Y

Using Law of Sines

$\dfrac{p}{\sin P} =\dfrac{q}{\sin Q}\\\dfrac{125}{\sin P} =\dfrac{184.87}{\sin 110}\\123 \times \sin P=125 \times \sin 110\\\sin P=(125 \times \sin 110) \div 184.87\\P=\arcsin [(125 \times \sin 110) \div 184.87]\\P=39^\circ $ (to the nearest degree)$

The direction of flight Y to the nearest degree is 39 degrees.

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