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Phoenix [80]
3 years ago
12

T-6=8-thow do solve? pls include steps

Mathematics
1 answer:
umka2103 [35]3 years ago
8 0
First, add t to each side:
2t - 6 = 8
Add 6 to each side:
2t = 14
Divide both sides by 2:
t = 7

Hope this helps!! :)
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What an equation for the translation of y=|x|. 13 unites down
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Answer:

\large\boxed{y=|x|-13}

Step-by-step explanation:

In this question, we're trying to make a new equation.

We know that:

  • We translated 13 units down

When it says down, we know that the y intercept would be changing.

Since there werer no y intercept or beginning point to start with, we know that before we translated, it was at 0.

Since we went down 13 units, we're subtracting 13 units from our original spot.

This means that we're going down -13.

When you put that into an equation, it should look like this:

y= |x| - 13

<h3>I hope this helped you out.</h3><h3>Good luck on your academics.</h3><h3>Have a fantastic day!</h3>
8 0
3 years ago
1/3 divided by 3 1/2
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Answer:

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Step-by-step explanation:

8 0
2 years ago
Find an equation of the line containing the centers of the two circles whose equations are given below.
Anna35 [415]

Answer:

<h2><em>3y+x = -5</em></h2>

Step-by-step explanation:

The general equation of a circle is expressed as x²+y²+2gx+2fy+c = 0 with centre at C (-g, -f).

Given the equation of the circles x²+y²−2x+4y+1  =0  and x²+y²+4x+2y+4  =0, to  get the centre of both circles,<em> we will compare both equations with the general form of the equation above as shown;</em>

For the circle with equation x²+y²−2x+4y+1  =0:

2gx = -2x

2g = -2

Divide both sides by 2:

2g/2 = -2/2

g = -1

Also, 2fy = 4y

2f = 4

f = 2

The centre of the circle is (-(-1), -2) = (1, -2)

For the circle with equation x²+y²+4x+2y+4  =0:

2gx = 4x

2g = 4

Divide both sides by 2:

2g/2 = 4/2

g = 2

Also, 2fy = 2y

2f = 2

f = 1

The centre of the circle is (-2, -1)

Next is to find the equation of a line containing the two centres (1, -2) and (-2.-1).

The standard equation of a line is expressed as y = mx+c where;

m is the slope

c is the intercept

Slope m = Δy/Δx = y₂-y₁/x₂-x₁

from both centres, x₁= 1, y₁= -2, x₂ = -2 and y₂ = -1

m = -1-(-2)/-2-1

m = -1+2/-3

m = -1/3

The slope of the line is -1/3

To get the intercept c, we will substitute any of the points and the slope into the equation of the line above.

Substituting the point (-2, -1) and slope of -1/3 into the equation y = mx+c

-1 = -1/3(-2)+c

-1 = 2/3+c

c = -1-2/3

c = -5/3

Finally, we will substitute m = -1/3 and c = 05/3 into the equation y = mx+c.

y = -1/3 x + (-5/3)

y = -x/3-5/3

Multiply through by 3

3y = -x-5

3y+x = -5

<em>Hence the equation of the line containing the centers of the two circles is 3y+x = -5</em>

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3 years ago
Write 108.92 in expanded form
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