1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Svet_ta [14]
3 years ago
15

First step for solving this quadratic equation? x2+2x-11=4

Mathematics
1 answer:
kenny6666 [7]3 years ago
3 0

Answer:

subtract 4 from both sides

Step-by-step explanation:

Given

x² + 2x - 11 = 4

First step : subtract 4 from both sides

x² + 2x - 15 = 0 ← in standard form

Second step : factorise the quadratic

(x + 5)(x - 3) = 0 ← in factored form

Third step : equate each factor to zero and solve for x

x + 5 = 0 ⇒ x = - 5

x - 3 = 0 ⇒ x = 3

Fourth step : state the solutions

solutions are x = - 5, x = 3

 

You might be interested in
What adds to 50 and multiplies to 70
kozerog [31]
Im thinking 10 because 10+40=50 and 10x7=70

5 0
3 years ago
Read 2 more answers
the empire state building is 1250 feet tall. IF an object is thrown upward from the top of the building at an initial velocity o
ss7ja [257]

Answer:

Time for the object to get h(max)    s = 1.1875 sec

h (max)  = 1272.57 feet

Down time for the object to hit the ground   =  4.25 sec

Step-by-step explanation:

The relation

h(s)  =  -  16*s²  +  38* s  + 1250    (1)

Is equivalent to the equation for vertical shot

Δh = V(i)*t  -  1/2g*t²  (in this case we don´t have independent term since the shot is from ground level. We can see in (1), the independent term is 1250 feet ( the height of the empire state building), the starting point of the movement.

The description of the movement is:

V(s)  =  V(i)  - g*s     ⇒  V(s) = 38 - 32*s

At h(max)    V(s)  =  0      38/32  = s

So the maximum height is at  s = t = 1.1875 sec

The time for the object to pass for starting point is the same

t  =  1.1875 sec

h(max) is

h(max)  = - 16* (1.1875)² +  38 (1.1875) + 1250

h(max)  =  -  22,56  +  45.13  +  1250

h(max)  =  1272.57 feet

Time for the object to hit the ground is

h(s)  =  - 1250 feet

-1250  =  - 16 s² + 38*s  + 1250

-16s² +  38s  =  0

s ( -16s + 38 )  =  0

First solution for that second degree equation  is x = 0 which we dismiss

then  

( -16s + 38 )  =  0    ⇒ 16s   =  38     s  =  38/16

s =  2.375 sec    and  we have to add time between h (max) and to get to starting point  ( 1. 1875 sec)

total time is  = 2.375 + 1.875

Total time  =  4.25 sec

4 0
3 years ago
PLEASE HELP BEEN STUCK FOR 20 MINS NOW!! i am struggling
topjm [15]
Circle = 360°

sector C = 0.35 · 360° = 126°
8 0
3 years ago
Find the factors of function g.
SashulF [63]
This will be 2400 cause there is nothing in the ones place
3 0
2 years ago
Please help me out.​
grandymaker [24]

Answer:

it's 4

Step-by-step explanation:

big brainnnnnnnnnn

6 0
3 years ago
Read 2 more answers
Other questions:
  • An angle is 74 degrees more than its complement. Find both angles.
    15·2 answers
  • Solve the system by substitution y=10x y=-3x-104
    14·1 answer
  • What's the Discriminant of X^2-2X-15 ?
    8·1 answer
  • Are the polygons similar if they are right a similarity statement and give the scale factor the figure is not drawn to scale
    12·2 answers
  • My number has a tens digit that is 8 more than the ones digit. zero is not one of mt digits.
    14·1 answer
  • Find the measure of C to the nearest degree.
    10·1 answer
  • Solve the equation -4.2 + - (0.6) divided by 6​
    8·1 answer
  • What is the truth value of "If yesterday was Tuesday then today is Wednesday"
    13·1 answer
  • A cookie factory uses 3 bags of flour in each batch of cookies. The factory used 2 7/10 bags of flour yesterday. How many batche
    12·1 answer
  • Find H of the shape.
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!