law's of exponents
e^(x-5)*e^(3x+8) = 19
e^(x-5+3x+8) = 19
e^(4x+3) = 19
take the natural log, which is base "e" of both sides.
ln[e^(4x+3)] = ln[19]
4x +3 = ln[19]
4x = ln[19] - 3
x = (ln[19] - 3) / 4
x = -0.0139
Sin Ф=opposite/ hypotenuse
In this case:
sin 25º=9 in /c
c=9 in/ sin 25º
c≈21.3 in.
Answer: sin (25º), in this case can be used to find the lenght of the hypotenuse, and the length of this hypotenuse would be 21.3 in.
I’m not the best at graphs but i did take algebra, i think it’s graph number 2. also i’m sorry if it’s wrong:(
8:30 am. A quarter of an hour is 15 min
