In a quadratic equation
q(x) = ax^2 + bx + c
The discriminant is = b^2 - 4ac
We have that discriminant = 3
If
b^2 - 4ac > 0, then the roots are real.
If
b^2 - 4ac < 0 then the roots are imaginary
<span>In
this problem b^2 - 4ac > 0 3 > 0 </span>
then
the two roots must be real
I am going to have to go with, C, because the other answers are Invalid.
It is B
(x+1<1)this mark(x+1>1)
Answer:
If Regina wants a mean of 90, she needs to sell 94 books on the 5th day.
