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Maslowich
4 years ago
8

How to convert the equation

="TexFormula1" title="y = \frac{q}{5 {}^{x} } " alt="y = \frac{q}{5 {}^{x} } " align="absmiddle" class="latex-formula">
to linear form​
Mathematics
1 answer:
polet [3.4K]4 years ago
8 0

Answer:

xlog 5 = logq - log y\\

Step-by-step explanation:

Given the equation y = \frac{q}{5^{x} }, to convert to linear form, the following steps must be followed;

5^{x} = \frac{q}{y}\\  y5^{x}  = q\\taking\ the\ log\ of\ both\ sides\\log(y5^{x}) = log q\\logy + log 5^{x} = log q\\log y + xlog5 = log q\\xlog 5 = logq - log y\\

The final expression is a linear form of the expression

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Which of the following uses the reciprocal property to rewrite x/12 = 32/18 ?
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Step-by-step explanation:

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4 years ago
In an assembly-line production of industrial robots, gearbox assemblies can be installed in one minute each if holes have been p
Illusion [34]

Answer:

The right answer is:

(a) 0.1456

(b) 18.125, 69.1202, 8.3139

Step-by-step explanation:

Given:

N = 24

n = 5

r = 7

The improperly drilled gearboxes "X".

then,

⇒ P(X) = \frac{\binom{7}{x} \binom {17}{5-x}}{\binom{24}{5}}

(a)

P (all gearboxes fit properly) = P(x=0)

                                               = \frac{\binom{7}{0} \binom{17}{5}}{\binom{24}{5}}

                                               = 0.1456

(b)

According to the question,

X = 91+5

Mean will be:

⇒ \mu = E(x)

       =E(91+5)

       =9E(1)+5

       =9.\frac{nr}{N}+5

       =9.\frac{5.7}{24} +5

       =18.125

Variance will be:

⇒ \sigma^2=Var(X)

         =V(9Y+5)

         =81.V(Y)

         =81.n.\frac{r}{N}.\frac{N-r}{N}.\frac{N-n}{N-1}

         =81.5.\frac{7}{24}.\frac{24-7}{24}.\frac{24-5}{24-1}

         =69.1202

Standard deviation will be:

⇒ \sigma = \sqrt{69.1202}

       =8.3139      

8 0
3 years ago
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