Answer:
CaI2
Here 2 will be small or lower like depicted in figure
Explanation:
CaI2 or Calcium Iodide is the ionic compound formed when calcium and Iodine react with each other. If we talk about physical properties it is a salt that is colorless and highly soluble in water. It is used a s a food for cats and other properties are similar to the salts of related type like calcium chloride.
It also takes part in many single displacement reaction, such as below mentioned where sodium displaces calcium with itself:
CaI2 + 2 Na → 2 NaI + Ca
Hope it helps!
1) 1
2)1600
3)0.109
4)0.250
5)14000
6)1000
7)4.8
8)0.027
9)0.198
10)0.075
11)0.50
12)5000
13)1.6
14)65000
15)25
16)0.355
17)0.08
18)63
19)560
20)260
21)0.0565
22)0.0275
23)9.23
24)2500
It was fun!
The reduction is solubility is because 3) of a common ion effect.
The common ion effect is when an ion that is already present in a solution is added, causing the following equilibrium to be disturbed:
AB ↔ [A+] + [B-]
If [B-] is added, then according to Le Chatelier's principle, the equilibrium must shift backward, creating more undissolved precipitate.<span />
D. Experiments provided new evidence about the atom, I think, sorry if I’m wrong
The mass of ammonia required to produce 2.40 × 10⁵ kg of (NH₄)₂SO₄ is 6.18 * 10⁴ Kg of ammonia.
<h3>What mass in kilograms of ammonia are required to produce 2.40 × 10⁵ kg of (NH₄)₂SO₄?</h3>
The mass of ammonia required to produce 2.40 × 10⁵ kg of (NH₄)₂SO₄ is determined from the mole ratio of the reaction.
The mole ratio of the reaction is obtained from the balanced equation of the reaction given below:
- 2NH₃(g) + H₂SO₄(aq) → (NH₄)₂SO₄(aq)
Mole ratio of NH₃ and (NH₄)₂SO₄ is 2: 1
Mass of 2 moles of ammonia = 2 * 17 = 34 g
Mass of 1 mole of (NH₄)₂SO₄ = 132 g
Mass of ammonia required = 34/132 * 2.40 × 10⁵ kg
Mass of ammonia required = 6.18 * 10⁴ Kg of ammonia.
In conclusion, the mole ratio is used to determine the mass of ammonia required.
Learn more about mole ratio at: brainly.com/question/19099163
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