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const2013 [10]
2 years ago
9

A compound is analyzed and found to be 50% sulfur and 50% oxygen. If the total amount of the sulfur oxide is 12.5 g, how many gr

ams of sulfur are there? Show work.
Chemistry
1 answer:
il63 [147K]2 years ago
7 0

Answer:

25.0g is the mass of sulfur

Explanation:

The sulfur and the oxygen are 50:50. That means there is 1 mole of S per mole of O.

To solve this question we need to convert the mass of O to moles, as moles of O = Moles of S, we can find the moles of S and its mass:

<em>Moles O = Moles S:</em>

12.5g O * (1mol / 16g) = 0.781 moles

<em>Mass S:</em>

0.781 moles * (32g / mol) =

<h3>25.0g is the mass of sulfur</h3>
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Answer:

Kc = 1.09x10⁻⁴

Explanation:

<em>HF = 1.62g</em>

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<em />

To solve this question we need to find the moles of each reactant in order to solve the molar concentration of each reactan and replacing in the Kc expression. For the reaction, the Kc is:

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<em>Because Kc is defined as the ratio between concentrations of products over reactants powered to its reaction coefficient. Pure liquids as water are not taken into account in Kc expression:</em>

<em />

[H₃O⁺] = 0.110g * (1mol /19.01g) = 0.00579moles / 5.6L = 1.03x10⁻³M

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Kc = [1.03x10⁻³M] [1.53x10⁻³M] / [0.0145M]

<h3>Kc = 1.09x10⁻⁴</h3>
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