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const2013 [10]
2 years ago
9

A compound is analyzed and found to be 50% sulfur and 50% oxygen. If the total amount of the sulfur oxide is 12.5 g, how many gr

ams of sulfur are there? Show work.
Chemistry
1 answer:
il63 [147K]2 years ago
7 0

Answer:

25.0g is the mass of sulfur

Explanation:

The sulfur and the oxygen are 50:50. That means there is 1 mole of S per mole of O.

To solve this question we need to convert the mass of O to moles, as moles of O = Moles of S, we can find the moles of S and its mass:

<em>Moles O = Moles S:</em>

12.5g O * (1mol / 16g) = 0.781 moles

<em>Mass S:</em>

0.781 moles * (32g / mol) =

<h3>25.0g is the mass of sulfur</h3>
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Explanation:

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Why do elements in the same group have similar physical and chemical properties
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Each element within a group has similar physical or chemical properties because of its atom's outermost electron shell (most chemical properties are dominated by the orbital location of the outermost electron).

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If a car passes a pedestrian, a change in pitch is __________.
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<span>1) If a car passes a pedestrian, a change in pitch is ______________. 
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Read 2 more answers
Name: _________________ Temperature o fwater_25_degreecent.YOU MUST SHOW ALL CALCULATIONS TO RECEIVE CREDIT FOR THEM! DATA ANALY
Anton [14]

Answer:

1. 0.02 M

2. 0.01 M

3. 4×10⁻⁶

Explanation:

We know that V₁S₁ = V₂S₂

1.

Concentration of HCl = 0.05 M

end point comes at = 10 ml

So, concentration of OH⁻(aq) = [OH⁻(aq)] ⇒ (0.05 × 10) ÷ 25 ⇒ 0.02 M

2.

2mol of OH⁻(aq) ≡ 1 mole of Ca²⁺(aq)

[Ca²⁺] = 0.02 ÷ 2 = 0.01 M

3.

K_{sp} = [Ca²⁺(aq)] [OH⁻(aq)]²

Ca(OH)₂ (aq) ⇄ Ca²⁺ (aq) + 2OH⁻ (aq)

K_{sp} = [0.01 × (0.02)²] = 4×10⁻⁶

4.

If reaction is exothermic which means heat energy will get evolved as a result temperature of the reaction media will get increased during the course of the reaction. If temperature is externally increased, the reaction will go backward to accumulate extra heat energy.

5.

K_{sp} value describes the solubility of a particular ionic compound. The higher the K_{sp} value, the higher the Solubility will be.

6.

This may be due to uncommon ion effect. The process of other ions (K⁺ or Na⁺) may increase the solubility

4 0
3 years ago
A ball is dropped from a height of 1.20 m and hits the floor. The ball compresses and then reforms to spring upwards from the fl
diamong [38]

Answer:

\large \boxed{\text{98 m$\cdot$s}^{-2}}

Explanation:

The formula for the velocity of the ball is

v = \sqrt{2gh}

1. Velocity at time of impact

v = -\sqrt{2 \times 9.807 \times 1.20} = -\sqrt{23.54} = -\textbf{4.85 m/s}

2. Velocity on rebound

The ball has enough upward velocity to reach a height of 0.86 m.

v = \sqrt{2 \times 9.807 \times 0.86} = \sqrt{16.87} =\textbf{4.11 m/s}

3. Acceleration

a = \dfrac{\Delta v}{\Delta t} = \dfrac{4.11 - (-4.85)}{ 0.091} = \dfrac{8.96 }{0.091} =\textbf{98 m$\cdot$s}^{\mathbf{-2}}\\\\\text{The acceleration while the ball is in contact with the floor is $\large \boxed{\textbf{98 m$\cdot$s}^{\mathbf{-2}}}$}

5 0
3 years ago
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