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Alex Ar [27]
3 years ago
10

Explain how you decided what number sentence to write for exercise 1 how to do that

Mathematics
1 answer:
Musya8 [376]3 years ago
8 0
The answer is 21 i really don't know 
You might be interested in
I need to know how to solve <br> -4-(2+4(-6)-4-(2^2-5*2))
sweet-ann [11.9K]

Answer:

16

Step-by-step explanation:

This problem requires PEMDAS

Parentheses ( )

Exponents ^

Multiplication

Division

Add

Subtract

Start by solving anything in parentheses. There's an exponent within the parentheses, so we change that 2^2 into 4 and also make sure to multiply 5 x 2 before subtracting.

-4 - (2 + -24 - 4 - (4-10))

-4 - (2 + -24 - 4 - (-6))

Again, solve parentheses first.

-4 - (-22 - 4 - (-6))

-4 - (-26 + 6)

-4 - (-20)

-4 + 20

Answer is 16

4 0
3 years ago
The table represents the total miles traveled, y, after a number of hours, x.
Annette [7]
60x=y

To find this answer, find what y/x=m would be for m
150/2.5=60
240/4= 60
330/5.5=60
420/7=60
3 0
3 years ago
Read 2 more answers
1. ONE AND TWO HUNDREDTHS AS A DÉCIMAl AND FRACTION
astraxan [27]

Answer:

1.02 as a decimal

1 and 1/50 as a fraction

Step-by-step explanation:

5 0
2 years ago
What is the number of real solutions? : 8x^2-11x=-3
swat32
X=1, and 3/8 it is a mixed number.

4 0
4 years ago
[Systems of equations] (/20) 1. Suppose the coefficient matrix of a system of linear equations has a pivot position in every row
Marina86 [1]

Answer:

The system is consistent because the rightmost column of the augmented matrix is not a pivot column.

Step-by-step explanation:

It is given that the coefficient of the matrix of a linear equation has a pivot position in every row.

It is provided by the Existence and Uniqueness theorem that linear system is said to be consistent when only  the column in the rightmost of the matrix which is augmented is not a pivot column.

When the linear system is considered consistent, then every solution set consists of either unique solution where there will be no any variables which are free or infinitely many solutions, when there is at least one free variable. This explains why the system is consistent.

For any m x n augmented matrix of any system, if its co-efficient matrix has a pivot position in every row, then there will never be a row of the form [0 .... 0 b].

6 0
3 years ago
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