Answer:
x intercepts: (1,0), (-3,0)
the roots are 1 and -3
Step-by-step explanation:
Using the Quadratic Formula:
x=−b±sqrt(b2−4ac)/2a
Substitute:
x= -8±sqrt(8^2-4(4)(-12))/2(4)
x=-8±sqrt((64- -192))/8
x=-8±sqrt(256)/8
Solve two equations (±)
x=-8±16/8
x=8/8 and x=-24/8
x=1 and x=-3
43.01
NEED MORE CHARECTERS HEEHEE
Answer:
The correct option is;

Step-by-step explanation:
The given parameters are
The equation of motion of one (the first) object is r = 4·cos(θ)
The equation of motion of the other (the second) object is r = -1 + 2·cos(θ)
Equating both equations gives;
4·cos(θ) = -1 + 2·cos(θ)
4·cos(θ) - 2·cos(θ) = -1
2·cos(θ) = -1
cos(θ) = -1/2
θ = Arccos(-1/2) = 120° = 2·π/3
Therefore, the two equations are equal when θ = 2·π/3 for which we have;
r = 4·cos(2π/3) = -2 and r = -1 + 2·cos(2π/3) = -2
∴ r = 4·cos(2π/3) = -1 + 2·cos(2π/3) = -2
The coordinate that represents a possible collision point of the objects in the form (r, θ) is therefore 
You moved 2 units left and then 2 units up.