Are u trying to find the volume? Or surface area or area?
Answer:
See below
Step-by-step explanation:
Ⓗⓘ ⓣⓗⓔⓡⓔ
Yay another one of these!
1) Corr. angles postulate
2) Division prop of equality
3) Division prop of equality
Tell me if you can't use the definitions more than once
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Please, please give brainliest, it would be greatly appreciated, I only a few more before I advance, thanks!
You are given two points on the line:
.. (1, 7) and (4, 5.5)
You can use the 2-point form of the equation for a line.
.. y = (y2-y1)/(x2-x1)*(x -x1) +y1
.. y = (5.5 -7)/(4 -1)*(x -1) +7
.. y = -0.5x +7.5
Your linear equation is y = -0.5x +7.5
Answer:
Angle between the two vectors is 135°
u•v = -12
Step-by-step explanation:
Given two vectors u = (4,0) and v = (-3,-3).
To find the angle between the two vectors we will use the formula for calculating the angle between two vectors as shown;
u•v = |u||v|cos theta
cos theta = u•v/|u||v|
theta = arccos (u•v/|u||v|)
u•v = (4,0)•(-3,-3)
u•v = 4(-3)+0(-3)
u•v = -12
For |u| and |v|
|u| = √4²+0²
|u| = √16 = 4
|v| = √(-3)²+(-3)²
|v| = √9+9
|v| = √18
|v| = 3√2
|u||v| = 4×3√2 = 12√2
theta = arccos(-12/12√2)
theta = arccos(- 1/√2)
theta = -45°
Since cos is negative in the second quadrant, theta = 180-45°
theta = 135°
To get u•v using the formula u•v = |u||v|cos theta
Given |u||v| = 12√2 and theta = 135°
u•v = 12√2cos 135°
u•v = 12√2× -1/√2
u•v = -12√2/√2
u•v = -12
For the diagram of the vectors, find it in the attachment below.