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son4ous [18]
4 years ago
12

PLEASE HELP WITH THIS!!!

Mathematics
1 answer:
n200080 [17]4 years ago
3 0
Only values |y| < 2 appear to be excluded. Those in the range are ...
  B. 3
  C. -4
  E. -2 . . . . . . this one is a "maybe." There is no dot (filled or open) to indicate whether the function is defined at (-4, -2) or not.
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12/8 es equivalente a 6/4<br>​
oksian1 [2.3K]

Answer:

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If the probability of one event occurring is .40 and the probability of a second event occurring is 0.60, then the probability t
diamong [38]

Let P(A)=0.4 and P(B)=0.6. The the probability both events occurring P(AB)=P(A)P(B|A)=P(B)P(A|B).

This shows P(AB) \leq \min(P(A),P(B)) \\ P(AB) \leq \min(0.4,0.6)\\ P(AB) \leq 0.4

If A and B are independent

P(AB)=P(A)P(B)=0.4*0.6=0.24

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3 years ago
8 sets of 3 positive tiles.
kramer

Answer:

A & E

Step-by-step explanation:

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4 years ago
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enyata [817]

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0.5

Step-by-step explanation:

I found this out because I am smart

7 0
3 years ago
A bag contains 8 red marbles, 4 white marbles, and 5 blue marbles. You draw one marble at random. Find P(red and blue) A. 40/17.
bogdanovich [222]
Sum of all marbles in the bag is 8+4+5 = 17.
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Now, because you are picking only 1 marble it is impossible for it to be both red and blue. You would need to pick at least 2 marbles to have a chance that one is red and one is blue.

The answer is B. 0
4 0
3 years ago
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