Question

In the following situation, determine whether you are asked to determine the number of permutations or combinations. Then

Answer 1

Answer:

The correct option is d.) 26C3 = 2600

Step-by-step explanation:

How many ways are there to pick a subset of 3 different letters from the 26-letter alphabet?

This a  selection problem therefore we will use combination.

Therefore to pick a subset of 3 different letters from the 26 letter alphabet is given by

$\binom{26}{3} = \frac{26!}{3!\times(26-3)!} = \frac{26\times25\times24}{6} = 2600$

Therefore the correct option is d.) 26C3 = 2600