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skad [1K]
3 years ago
15

I would like some help on this please. :) The attachment is below.

Mathematics
1 answer:
nika2105 [10]3 years ago
4 0

tn = 1-4n

t12 = 1-4*12

t12 = 1-48

t12 = -47



tn =1/2 n+3/2

t12 = 1/2 (12) + 3/2

t12 = 12/2 + 3/2

t12 = 15/2

t12 = 7 1/2




9,4,-1

a1=9

d = 4-9 =-5

an =a1+d(n-1)

-146 = 9 + -5(n-1)

subtract 9 from each side

-155= -5(n-1)

divide by -5

31 = n-1

add 1 to each side

n=32

the 32nd term is -146


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I’ll give brainlist award please answer
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For answering multiple choice, you can do the following:

Observe the diagram, noting that one curve has positive slope, and the other has negative slope.
Looking at the equations,
if x and y are on the same side of the equal sign, (which is the case here), then
- coefficients of x and y have equal signs (both+, or both -) then the equation has negative slope.
- coefficients of x and y have different signs (+-, or -+), then the equation has positive slope.
We see the second system has both equations with positive slope, and the third system has both equations with negative slopes.  They're out!

Next, we check the y-intercept of the first equation (by setting x=0),
first system: 0+2y=-10 => y-intercept=-5, slope=-1/2 Good
fourth system: 0-2y=-10 => y-intercept=+5  No good.

Finally, check the x-intercept of the second equation of the first system (by setting y=0)
first system: 3x-0=12 => x-intercept = 12/3=+4, slope = +3  good

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Doe's anyone understand this?
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just subtracting by 2x on both sides

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Inverse Function -5 + 5/2x
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Answer:

y = (2/5)x + 2

Step-by-step explanation:

To find the inverse of a function, we simply exchange the variables x and y and solve for y.

For this function we will write it as such:

y = -5 + (5/2)x

So to find the inverse, we will swap the x and y and solve.

y = -5 + (5/2)x

x = -5 + (5/2)y

x + 5 = (5/2)y

(2/5) * (x + 5) = y

(2/5)x + (2/5)5 = y

(2/5)x + 2 = y

Thus the inverse of the function is:

y = (2/5)x + 2

Cheers.

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3 years ago
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Answer:

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<u />

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x(7x^7+613.76)  =<u>x(7x^7+613.76)</u>

<u />

<h3><em><u>brainliest please?</u></em></h3>
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