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Anit [1.1K]
3 years ago
8

FAST......................

Mathematics
1 answer:
SIZIF [17.4K]3 years ago
8 0

Answer:

ti is m(B{AC=70*

Step-by-step explanation:

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BRAINLIEST if correct<br><br><br><br><br> 4
Viefleur [7K]

Answer:

Yes it is biased

Step-by-step explanation:

It shows favoritism

4 0
3 years ago
Read 2 more answers
Suppose that your net income for the month is 1500 and that your total expenses are 2500 which statement is accurate?
mestny [16]

C. you have a deficit of 1000

Explanation:

We say that we have a surplus when the net income is more than the total expenses, while we say that we have a deficit when the net income is less than the total expenses.

In this case, the net income is 1500, which is less than the total expenses (2500): so, we have a deficit. In order to calculate the deficit, we can use the formula

deficit = total expenses - net income

Substituting the data of the problem, we find

deficit = 2500 - 1500 = 1000

7 0
3 years ago
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Aflati un numar stiind ca 1/3 din 1/1/3 din el este 40 VA ROG MULT DAU COROANA
I am Lyosha [343]

Answer:

This is such a unique language. What language is this? I wanna try and learn it

6 0
3 years ago
This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive an
sleet_krkn [62]

Answer:

-6re−r [sin(6θ) - cos(6θ)]

Step-by-step explanation:

the Jacobian is ∂(x, y) /∂(r, θ) = δx/δθ × δy/δr - δx/δr × δy/δθ

x = e−r sin(6θ), y = er cos(6θ)

δx/δθ = -6rcos(6θ)e−r sin(6θ), δx/δr = -sin(6θ)e−r sin(6θ)

δy/δθ = -6rsin(6θ)er cos(6θ), δy/δr = cos(6θ)er cos(6θ)

∂(x, y) /∂(r, θ) =  δx/δθ × δy/δr - δx/δr × δy/δθ

= -6rcos(6θ)e−r sin(6θ) × cos(6θ)er cos(6θ) - [-sin(6θ)e−r sin(6θ) × -6rsin(6θ)er cos(6θ)]

= -6rcos²(6θ)e−r (sin(6θ) - cos(6θ)) - 6rsin²(6θ)e−r (sin(6θ) - cos(6θ))

= -6re−r (sin(6θ) - cos(6θ)) [cos²(6θ) + sin²(6θ)]

= -6re−r [sin(6θ) - cos(6θ)]     since  [cos²(6θ) + sin²(6θ)] = 1

6 0
3 years ago
Drag the simplified value into the box to match each expression.
AveGali [126]

Answer:

2^{3} +1⋅4−3 = 9

2^{0}+10−4⋅2 = 3

3+5^{2} -6⋅4 = 4

Step-by-step explanation:

4 0
3 years ago
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