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3 years ago

Can someone help me with this problem??

Mathematics

2 answers:

DIA [1.3K]3 years ago

8 0

∠DAB and ∠BAC (arc BC) are supplementary angles, angles which add up to 180°.

∠DAB + ∠BAC = 180°
26° + ∠BAC = 180°
∠BAC = 180° - 26°
∠BAC = 154°

The measure of ∠BAC (arc BC) is 154 degrees

Butoxors [25]3 years ago

6 0

Never mind, i don't know i'm sorry

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Find the value of y.

Alchen [17]

The 'Y' Coordinate is written second in an order of coordinates which is /X , Y\ Prob such as /12, 5\

3 0

3 years ago

Jane must get at least three of the four problems on the exam correct to get an A. She has been able to do 80% of the problems o

NISA [10]

Answer:

a) There is n 81.92% probability that she gets an A.

b) If she gets the first problem correct, there is an 89.6% probability that she gets an A.

Step-by-step explanation:

For each question, there are only two possible outcomes. Either the answer is correct, or it is not. This means that we can solve this problem using binomial distribution probability concepts.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

For this problem, we have that:

The probability she gets any problem correct is 0.8, so $\pi = 0.8$ .

(a) What is the probability she gets an A?

There are four problems, so $n = 4$

Jane must get at least three of the four problems on the exam correct to get an A.

So, we need to find $P(X \geq 3)$

$P(X \geq 3) = P(X = 3) + P(X = 4)$

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 3) = C_{4,3}.(0.80)^{3}.(0.2)^{1} = 0.4096$

$P(X = 4) = C_{4,4}.(0.80)^{4}.(0.2)^{0} = 0.4096$

$P(X \geq 3) = P(X = 3) + P(X = 4) = 2*0.4096 = 0.8192$

There is n 81.92% probability that she gets an A.

(b) If she gets the first problem correct, what is the probability she gets an A?

Now, there are only 3 problems left, so $n = 3$

To get an A, she must get at least 2 of them right, since one(the first one) she has already got it correct.

So, we need to find $P(X \geq 2)$

$P(X \geq 3) = P(X = 2) + P(X = 3)$

$P(X = 2) = C_{3,2}.(0.80)^{2}.(0.2)^{1} = 0.384$

$P(X = 4) = C_{3,3}.(0.80)^{3}.(0.2)^{0} = 0.512$

$P(X \geq 3) = P(X = 2) + P(X = 3) = 0.384 + 0.512 = 0.896$

If she gets the first problem correct, there is an 89.6% probability that she gets an A.

3 0

3 years ago

A parabola has zeros at (5,0) and (-3,0) and passes through point (6,18) determine the axis of symmetry

worty [1.4K]

Answer:

The axis of symmetry is $x=1$

Step-by-step explanation:

we know that

In a vertical parabola, the axis of symmetry is equal to the x-coordinate of the vertex

In this problem we have a vertical parabola open upward

The x-coordinate of the vertex is equal to the midpoint between the zeros of the parabola

$x=\frac{5-3}{2}=1$

therefore

The axis of symmetry is $x=1$

5 0

3 years ago

Determine whether each relation is a function. Give the domain and range for each relation.

brilliants [131]

Answer:

Not a function

Domain: {3,4}

Range: {4,5}

Step-by-step explanation:

A function is a relation where each input has its own output. In other words if the x value has multiple corresponding y values then the relation is not a function

For the relation given {(3, 4), (3, 5), (4, 4), (4, 5)} the x value 3 and 4 have more than one corresponding y value therefore the relation shown is not a function

Now let's find the domain and range.

Domain is the set of x values in a relation.

The x values of the given relation are 3 and 4 so the domain is {3,4}

The range is the set of y values in a relation

The y value of the given relation include 4 and 5

So the range would be {4,5}

Notes:

The values of x and y should be written from least to greatest when writing them out as domain and range.

They should be written inside of brackets

Do not repeat numbers when writing the domain and range

3 0

2 years ago

Find the linear approximation of f(x)=lnx at x=1 and use it to estimate ln(1.38).

RideAnS [48]

$\bf f(x)=y=ln(x)\qquad 
\begin{cases}
x=1\\
y=ln(1)\to y=0
\end{cases}\\\\
-----------------------------\\\\
\left. \cfrac{dy}{dx}=\cfrac{1}{x} \right|_{x=1}\implies 1\impliedby m
\\\\\\
\textit{now, we know that }
\begin{cases}
x=1\\
y=0\\
m=1
\end{cases}\implies y-0=1(x-1)\implies y=x-1$

now, you're asked to use it when ln(1.38), which is just another way of saying x = 1.38

so set x = 1.38 and see what "y" is

5 0

3 years ago