Michelle found a new violin on sale at 30% off. how much would she pay the cashier if it originally sells for $250 in a city tha
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Answer:
Step-by-step explanation:
<em><u>Given</u></em><u>:</u> A line m is perpendicular to the angle bisector of ∠A. We call this
intersecting point as D. Hence, in figure ∠ADM=∠ADN =90°.
AD is angle bisector of ∠A. Hence, ∠MAD=∠NAD.
<u><em>To Prove</em></u>: <em><u>ΔAMN is an isosceles triangle. i.e any two sides in ΔAMN are</u></em>
<em> </em><em><u>equal. </u></em>
<em><u>Solution</u></em>: Now, In ΔADM and ΔADN
∠MAD=∠NAD ...(1) (∵Given)
AD=AD ...(2) (∵common side)
∠ADM=∠ADN ...(3) (∵Given)
<u><em> Hence, from equation (1),(2),(3) ΔADM ≅ ΔADN</em></u>
( ∵ ASA congruence rule)
⇒<u><em> AM=AN</em></u>
Now, In Δ AMN
AM=AN (∵ Proved)
Hence, ΔAMN is an isosceles triangle.
Answer:
Step-by-step explanation:
Use the zero-interval test [test point (0, 0)] to verify them as false or true, and to determine whether we shade the shared opposite portions [a shared portion that does NOT contain the origin] or the shared portions that DO contain the origin:
So, this system will be shaded in a shared opposite portion.
*NOTE; Both inequalities have an identical y-intercept of so both inequalities must intersect the y-axis at
and since there are already lines labeled as <em>dashed</em><em> </em>and solid, we do not have to worry about it in this case.
** None of the other graphs match this, so the bottom right graph has to be it, considering it cut off.
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