Answer:
y = -2.5
Step-by-step explanation:
For such a problem as this, you can replace all sine or cosine functions with their midline value of 0. Then you have ...
f(x) = 0 -2.5
which simplifies to ...
f(x) = -2.5
You can leave the equation like this, or write it as ...
y = -2.5
_____
Perhaps you can see that the midline is the value of any constant added to a sine or cosine function.
Answer:
x^2 + (y+1)^2 = 10^2
Step-by-step explanation:
Centre (p,q) = (0, -1)
radius, r = 10
General Equation of a circle
(x-p)^2 + (y-q)^2 = r^2
(x-0)^2 + (y- -1)^2 = 10^2
x^2 + (y+1)^2 = 10^2
Answer:
Step-by-step explanation:
The only thing you need to watch carefully is the divisor which in this case is x - 3. The divisor, in synthetic division, is the number that will make the binomial go to 0.
x - 3 =0
x = 3
So the divisor is 3.
3 || 2 4 -35 15
6 30 -15
======================
2 10 -5 0
So the quotient is
2x^2 + 10x - 5 with no remainder
Answer:
Step-by-step explanation:
a. sin^-1(sin theta) = theta
(1/sin)(sin theta) = theta
<em>the sines cross out</em> theta = theta
b. cos(cos^-1x) = x
cos(x/cos) = x
<em>the cosines cross out </em>x = x
Side XZ needs to be congruent to side AC. The answer is D.
