Question

Solve for x n(17+ x) = 34z - r

Answer 1

Hello!

The answer is:

$x=\frac{34z-r}{n}-17$

Why?

To solve for "x" , we just need to isolate it from the equation.

So, we are given the equation:

$n(17+x)=34z-r$

Then, isolating we have:

$n(17+x)=34z-r\\\\17+x=\frac{34z-r}{n}\\\\x=\frac{34z-r}{n}-17$

Hence, the answer is:

$x=\frac{34z-r}{n}-17$

Have a nice day!

Answer 2

Answer:

$x=\frac{34z-r}{n}-17$

Step-by-step explanation:

Given

$n(17+x)=34z-r$

We have to isolate x on one side of the equation

Dividing both sides by n

$\frac{n(17+x)}{n} =\frac{34z}{n}-\frac{r}{n}$

Taking LCM on left side

$17+x = \frac{34z-r}{n}$

Subtracting 17 from both sides

$17+x-17 = \frac{34z-r}{n}-17$

So, the value of x will be:

$x=\frac{34z-r}{n}-17$ ..