Question

A square has sides of length s. A rectangle is 6 inches shorter and 1 inch longer than the square. Which of the following polynomials represents the area of the rectangle? Select all that apply.

Answer 1

S - side of the square
rectangle
s-6
s+1
A =Length*Width
A=(s-6)(s+1)
A=s²-6s+s-6=s²-5s-6

Answer 2

Answer:

$(s-6)(s+1)\text {and }s^2-5s-6$

Step-by-step explanation:

Allow me add in all applies and hope it will fit the original one. Please have a look at the attached photo.

Given:

Length of the square: s

Because the rectangle is 6 inches shorter: s-6

and 1 inch longer than the square: s+1

=> the area of the rectangle is:

A = (s-6)(s+1)

<=> A = $s^{2} -6s + s -6$

<=> A = $s^{2} + 5s -6$

Thus , area of rectangle can be given by expressions:

$(s-6)(s+1)\text {and }s^2-5s-6$