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3 years ago

If f(x) = 5x + 40, what is f(x) when x= -5?

Mathematics

1 answer:

Marianna [84]3 years ago

8 0

Answer:

Hello!!! Princess Sakura here ^^

Step-by-step explanation:

$5x+40\\5(-5)+40\\-25+40\\15$

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The cost of producing x soccer balls in thousands of dollars is represented by h(x) = 5x + 6. The revenue is represented by k(x)

Korolek [52]

(9x-2) - (5x+6) =

4x-8 , this is your profit function

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3 years ago

Read 2 more answers

Find x<br> 5[x^2]+5[x]-x^2-x=2004

a_sh-v [17]

The answer is either $x=\frac{-1}{2}+\frac{1}{2}\sqrt{2005}\\$ or $x=\frac{-1}{2}+\frac{-1}{2}\sqrt{2005}$

To solve: Let's solve your equation step-by-step.

5x2+5x−x2−x=2004

Step 1: Simplify both sides of the equation.

4x2+4x=2004

Step 2: Subtract 2004 from both sides.

4x2+4x−2004=2004−2004

4x2+4x−2004=0

Step 3: Use quadratic formula with a=4, b=4, c=-2004.

x= −b±√b2−4ac /2a

x= −4±√32080 /8

$x=\frac{-1}{2}+\frac{1}{2}\sqrt{2005}\\$ or $x=\frac{-1}{2}+\frac{-1}{2}\sqrt{2005}$

4 0

3 years ago

Read 2 more answers

Expanded form: (4a+4b)^3

TiliK225 [7]

Step-by-step explanation:

use the formula: (a+b)³ = a³+3a²b+3ab²+b³

and place the corresponding values.

7 0

3 years ago

Evaluate the surface integral:S

rjkz [21]

Assuming $S$ does not include the plane $z=0$ , we can parameterize the region in spherical coordinates using

$\mathbf r(u,v)=\left\langle3\cos u\sin v,3\sin u\sin v,3\cos v\right\rangle$

where $0\le u\le2\pi$ and $0\le v\le\dfrac\pi/2$ . We then have

$x^2+y^2=9\cos^2u\sin^2v+9\sin^2u\sin^2v=9\sin^2v$
$(x^2+y^2)=9\sin^2v(3\cos v)=27\sin^2v\cos v$

Then the surface integral is equivalent to

$\displaystyle\iint_S(x^2+y^2)z\,\mathrm dS=27\int_{u=0}^{u=2\pi}\int_{v=0}^{v=\pi/2}\sin^2v\cos v\left\|\frac{\partial\mathbf r(u,v)}{\partial u}\times \frac{\partial\mathbf r(u,v)}{\partial u}\right\|\,\mathrm dv\,\mathrm du$

We have

$\dfrac{\partial\mathbf r(u,v)}{\partial u}=\langle-3\sin u\sin v,3\cos u\sin v,0\rangle$
$\dfrac{\partial\mathbf r(u,v)}{\partial v}=\langle3\cos u\cos v,3\sin u\cos v,-3\sin v\rangle$
$\implies\dfrac{\partial\mathbf r(u,v)}{\partial u}\times\dfrac{\partial\mathbf r(u,v)}{\partial v}=\langle-9\cos u\sin^2v,-9\sin u\sin^2v,-9\cos v\sin v\rangle$
$\implies\left\|\dfrac{\partial\mathbf r(u,v)}{\partial u}\times\dfrac{\partial\mathbf r(u,v)}{\partial v}\|=9\sin v$

So the surface integral is equivalent to

$\displaystyle243\int_{u=0}^{u=2\pi}\int_{v=0}^{v=\pi/2}\sin^3v\cos v\,\mathrm dv\,\mathrm du$
$=\displaystyle486\pi\int_{v=0}^{v=\pi/2}\sin^3v\cos v\,\mathrm dv$
$=\displaystyle486\pi\int_{w=0}^{w=1}w^3\,\mathrm dw$

where $w=\sin v\implies\mathrm dw=\cos v\,\mathrm dv$ .

$=\dfrac{243}2\pi w^4\bigg|_{w=0}^{w=1}$
$=\dfrac{243}2\pi$

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3 years ago

the table shows the ratio between the number of books ordered and their cost. 7,14 8,16 9,18. find equivalent ratios when the nu

Nadya [2.5K]

Answer:

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2 years ago