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Readme [11.4K]
3 years ago
11

Determine whether the pair of figures is similar.

Mathematics
2 answers:
pogonyaev3 years ago
7 0

Answer:

The triangles are similar

Step-by-step explanation:

You first flip the first triangle so the hypotenuse is facing the bottom right like the second triangle and the 49 degrees would be matching the same side as the picture would depict

You can then use the equaation 43 + 49 + x = 180 to solve for the missing angle in the second right triangle.

92 + x = 180

x = 88

The degrees match up, you then have to compare the sides.

You can first check the ratios between the same sides of the different triangles.

2.8 : 8.4

4 : 12

3.1 : 9.3

all of these ratios would be simplified to a 1:3 ration, meaning all the sides are proportional, making the triangles similar.

pogonyaev3 years ago
5 0

Answer:

answered in comments :)

Step-by-step explanation:

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4 years ago
The sum of two numbers is 62 the smaller number is 6 less than the larer number what are the numbers
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X= larger number
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3 years ago
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3 years ago
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Step-by-step explanation:

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3 years ago
In the adjoining figure , APB and AQC are equilateral triangles. Prove that PC = BQ. ( Hint : <img src="https://tex.z-dn.net/?f=
just olya [345]

Answer:

See Below.

Step-by-step explanation:

Statements:                                                           Reasons:

\displaystyle 1)\text{ } \Delta APB \text{ and } \Delta AQC \text{ are equilateral triangles}      Given

\displaystyle 2) \text{ } m \angle PAB = 60                                                     Definition of equilateral.

3)\text{ } m \angle QAC = 60                                                     Definition of equilateral.

4)\text{ } m\angle PAB = m\angle QAC                                          Substitution

5)\text{ } m\angle PAC=m\angle PAB+m\angle BAC                       Angle Addition

\displaystyle 6)\text{ } m\angle QAB=m\angle QAC+m\angle BAC                       Angle Addition

7)\text{ } m\angle QAB=m\angle PAB+m\angle BAC                       Substitution

\displaystyle 8)\text{ } m\angle PAC=m\angle QAB                                         Substitution

9)\text{ } PA=BA                                                          Definition of equilateral

10)\text{ } AC=AQ                                                        Definition of equilateral

\displaystyle 11)\text{ } \Delta PAC \cong \Delta BAQ                                            Side-Angle-Side Congruence*

\displaystyle 12)\text{ } PC=BQ                                                        CPCTC

* SAS Congruence:

PA = BA

∠PAC = ∠QAB

AC = AQ

6 0
3 years ago
Read 2 more answers
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