Answer:
Then the correct answer would be to two decimal places. Credit to 25rx0162.
Step-by-step explanation
Hope this helps : )
Answer:
68
Step-by-step explanation:
We let the random variable X denote the height of students of the college. Therefore, X is normally distributed with a mean of 175 cm and a standard deviation of 5 centimeters.
We are required to determine the percent of students who are between 170 centimeters and 180 centimeters in height.
This can be expressed as;
P(170<X<180)
This can be evaluated in Stat-Crunch using the following steps;
In stat crunch, click Stat then Calculators and select Normal
In the pop-up window that appears click Between
Input the value of the mean as 175 and that of the standard deviation as 5
Then input the values 170 and 180
click compute
Stat-Crunch returns a probability of approximately 68%
The answer is
date
1 2 3 4 5 31
r1 r2 r3 r4 r5 . . . r31
1gm 2gms 3<span>gms 4gms 5gms . . . 31gms
r1+r2+ .... +r31= 31(31+1) /2=496gms (31 rings)
he only made 5 rings
31 rings----------> 496 gms
5 rings ------------> ? = 5 x496 / 31=80 gms
</span><span> the weights of those 5 rings was 80 gms</span>
I think the answer is 816cm