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2 years ago

What is the slope of a line that is parallel to the line represented by the equation x-y=8

Mathematics

1 answer:

coldgirl [10]2 years ago

6 0

The slope of x-y=8 is 1 because it's actually y = x-8

Parallel means the slope is equal to 1 as well.

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Please Help me with this problem!!! ASAP

castortr0y [4]

The average rate of change is -5 per month

<h3>How to determine the average rate of change?</h3>

The interval is given as:

July to December

From the graph, we have:

July = 110

December = 30

The average rate of a function over the interval (a, b) is calculated as:

Rate = [f(b) - f(a)]/[b - a]

So, we have:

Rate = (30 - 110)/(December- July)

This gives

Rate = (30 - 110)/(12 - 7)

Evaluate

Rate = -16

Hence, the average rate of change is -5 per month

Read more about average rate of change at:

brainly.com/question/23715190

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6 0

1 year ago

Simplify 5(x+3) -9x+4

laiz [17]

Answer:

$=5x+15-9x+4\\=-4x+19\\$

5 0

2 years ago

Read 2 more answers

Help find the value of x

Nookie1986 [14]

Answer:

x = 82

Step-by-step explanation:

The bottom angle is the same as the angle next to x + 6

A straight angle is 180 degrees.

You add the given angles: (x + 6) + (x + 10) = 2x + 16

180 = 2x + 16

- 16 -16

164 = 2x

x = 82

8 0

2 years ago

emmasim [6.3K]

Answer:

The answer is B

Step-by-step explanation:

hope this helps

5 0

2 years ago

An automobile company wants to determine the average amount of time it takes a machine to assemble a car. A sample of 40 times y

aksik [14]

Answer:

A 98% confidence interval for the mean assembly time is [21.34, 26.49] .

Step-by-step explanation:

We are given that a sample of 40 times yielded an average time of 23.92 minutes, with a sample standard deviation of 6.72 minutes.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample average time = 23.92 minutes

s = sample standard deviation = 6.72 minutes

n = sample of times = 40

$\mu$ = population mean assembly time

<em> Here for constructing a 98% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation. </em>

<u>So, a 98% confidence interval for the population mean, </u> $\mu$ <u> is; </u>

P(-2.426 < $t_3_9$ < 2.426) = 0.98 {As the critical value of z at 1% level

of significance are -2.426 & 2.426}

P(-2.426 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.426) = 0.98

P( $-2.426 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.426 \times {\frac{s}{\sqrt{n} } }$ ) = 0.98

P( $\bar X-2.426 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.426 \times {\frac{s}{\sqrt{n} } }$ ) = 0.98

<u>98% confidence interval for</u> $\mu$ = [ $\bar X-2.426 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+2.426 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $23.92-2.426 \times {\frac{6.72}{\sqrt{40} } }$ , $23.92+2.426 \times {\frac{6.72}{\sqrt{40} } }$ ]

= [21.34, 26.49]

Therefore, a 98% confidence interval for the mean assembly time is [21.34, 26.49] .

7 0

2 years ago