What is the slope of a line that is parallel to the line represented by the equation x-y=8

Mathematics

1 answer:

coldgirl [10]3 years ago

6 0

The slope of x-y=8 is 1 because it's actually y = x-8

Parallel means the slope is equal to 1 as well.

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so any other vector that has a negative reciprocal slope to it, will then be perpendicular or "orthogonal" to it.

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or using a unit vector for those above, then

$\bf \textit{unit vector}\qquad \cfrac{\ \textless \ a,b\ \textgreater \ }{||\ \textless \ a,b\ \textgreater \ ||}\implies \cfrac{\ \textless \ a,b\ \textgreater \ }{\sqrt{a^2+b^2}}\implies \cfrac{a}{\sqrt{a^2+b^2}},\cfrac{b}{\sqrt{a^2+b^2}}
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