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tensa zangetsu [6.8K]
3 years ago
9

What is the solution to the system of equations? {−2x+5y=−163x−4y=17 (−2, 3) (−3, −425) (813, 2) (3, −2)

Mathematics
1 answer:
Hunter-Best [27]3 years ago
7 0

Answer:

Step-by-step explanation:

-2x + 5y = -16

3x - 4y = 17

-6x + 15y = -48

6x -    8y = 34

7y = -14

y = -2

3x + 8 = 17

3x = 9

x = 3

(3, -2)

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Simplify.... 
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3 years ago
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Roger sees water balloons fall past his window. He notices that each balloon strikes the sidewalk 1.01 s after passing his windo
vodomira [7]

Part A The balloon is travelling at 19.8 m/s when it passes Roger's window

Part B The balloon was released from the 7th floor.

To solve the questions, we need to use the equations of motion

<h3>What are equations of motion?</h3>

Equations of motion are equations used to solve for the motion of an object under a constant acceleration

<h3>Part A How fast are the balloons traveling when they pass Roger's window?</h3>

Since Roger sees water balloons fall past his window and he notices that each balloon strikes the sidewalk 1.01 s after passing his window. Roger's room is on the third floor, 15 m above the sidewalk.

Using the equation of motion s = ut - 1/2gt² where

  • s = height of Roger's room above sidewalk = 15 m,
  • u = speed of balloon at Roger's window,
  • t = time it takes balloon to reach sidewalk = 1.01 s and
  • g = acceleration due to gravity = 9.8 m/s²

Making u subject of the formula, we have

u = s/t + 1/2gt

Substiting the values of the variables into th equation, we have

u = s/t + 1/2gt

u = 15 m/1.01 s + 1/2 × 9.8 m/s² × 1.01 s

u = 14.851 m/s + 1/2 × 9.898 m/s

u = 14.851 m/s + 4.949 m/s

u = 19.8 m/s

So, the balloon is travelling at a speed of 19.8 m/s when it passes Roger's window

<h3>Part B From what floor are they being released</h3>

Since the balloons are released from rest, they have zero velocity.

So, using the equation of motion

v² = u² - 2gh where

  • u = initial velocity of balloon = 0 m/s (since it is released from rest),
  • v = speed of balloon at Roger's window = 19.8 m/s,
  • g = acceleration due to gravity = 9.8 m/s² and
  • h = height which balloon was released

Making h subject of the formula, we have

h = (v² - u²)/2g

Substituting the values of the variables into ther equation,we have

h = (v² - u²)/2g

h = [(19.8 m/s)² - (0 m/s²)]/2(9.8 m/s²)

h = 392.04 m²/s²/19.6 m/s²)

h = 20 m

Since each floor is 5 m high, so a height of 20 m would be 20 m/5 m = 4 floors.

So, this is 4 floors above Roger's room.

Since roger's room is on the 3rd floor, then 4 floors + 3 floors = 7 floors.

So, the balloon was released from the 7th floor.

Learn more about equations of motion here:

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Answer: d = 10

Step-by-step explanation:

Step-by-step explanation:

The formula for calculating distance between two points is given by :

d = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}

x_{1} = -3

x_{2} = 5

y_{1} = 11

y_{2} = 5

substituting the values , we have

d = \sqrt{(5-(-3))^{2}+(5-11)^{2}}

d = \sqrt{(5+3)^{2}+(-6)^{2}}

d = \sqrt{(8)^{2}+(-6)^{2}}

d = \sqrt{64+36}

d = \sqrt{100}

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