Answer:
3/8
Step-by-step explanation:
The possible outcomes
TTT TTH THT THH HHH HHT HTH HTT = 8 outcomes
There are TTH THT HTT 3 with exactly two tails
P ( exactly 2 tails) = 3/8
They used 20, 1 quart containers of milk.
Answer:
The percentage of the bag that should have popped 96 kernels or more is 2.1%.
Step-by-step explanation:
The random variable <em>X</em> can be defined as the number of popcorn kernels that popped out of a mini bag.
The mean is, <em>μ</em> = 72 and the standard deviation is, <em>σ</em> = 12.
Assume that the population of the number of popcorn kernels that popped out of a mini bag follows a Normal distribution.
Compute the probability that a bag popped 96 kernels or more as follows:
Apply continuity correction:


*Use a <em>z</em>-table.
The probability that a bag popped 96 kernels or more is 0.021.
The percentage is, 0.021 × 100 = 2.1%.
Thus, the percentage of the bag that should have popped 96 kernels or more is 2.1%.
22/29 = 0.76
0.76*100 = 76
You got a 76%