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tatuchka [14]
4 years ago
13

How to use implicit differentiation to find an equation of the tangent line?

Mathematics
1 answer:
Arada [10]4 years ago
5 0
The slope of the line is the dy/dx value every time it appears in the differential equation. By substituting values for x and y in the DE, the slope can be found for the tangent at a point. This is the value of m in y=mx+a. To find a, plug in the tangent point.
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You have quarters and dimes that total $2.80. your friends says its possible that the number of quarters is 8 more than the numb
Sidana [21]

\text{Let the number of dimes be x, then as per the friend the number of }\\
\text{quarters should be 8 more than dimes, so number of quarters}=x+8\\
\\
\text{we know that the value of 1 dime is }\$ 0.10 \text{ value of one quarter is }\$0.25\\
\\
\text{And since the total value of quarters and dimes is }\$2.80, \text{ so we have}\\
\\
0.10(x)+0.25(x+8)=2.80\\
\\
\Rightarrow 0.10x+0.25x+2=2.80\\
\\
\Rightarrow 0.35x=2.80-2\\
\\
\Rightarrow 0.35x=0.80

\Rightarrow x=\frac{0.80}{0.35}=2.29\\
\\
\text{so if we take 2 dimes then we'll have to take 10 quarters according to friend.}\\
\\
\text{So the statement of friend is } WRONG

6 0
3 years ago
The ratio of the number of boys to the number of girls in the school is 11 : 13 there are 72 less boys in the school how many ki
professor190 [17]
Lets:
x=number of boys.
y=number of girls

We can suggest this system of equations:
x/y=11/13      ⇒x=11y /13
x=y-72

We can solve this system by substitution method
(11y/13)=y-72
lower common multiple=13
11y=13y-936
11y-13y=-936
-2y=-936
y=-936/-2
y=468

x=11y/13=11(468)/13=396

There are 396 boys and 468 girls in this school,
number of kids=number of boys + number of girls.
number of kids=396+468=864

Answer: there are 864 kids in this school. 
4 0
3 years ago
Given the triangle below, tell me if it's a right triangle or not. Then, explain your answer with evidence.
padilas [110]
No because the triangle’s angle is less than 90 degrees if it was a right angle triangle it would have a square marking the angle.
6 0
3 years ago
Find all the zeroes of the function f(x)=11x^2+x+5
Rufina [12.5K]

Answer:

x = \frac{1 + \sqrt{(-219)} }{22} , \space  x = \frac{1 - \sqrt{(-219)} }{22}

Step-by-step explanation:

f(x)=11x^2+x+5 is the given equation,

now comparing it with the  standard equation ax^{2} + bx + c = 0, we get

11x^{2} + x + 5 = 0

Here, a = 11, b = 1 and c = 5

Now  by QUADRATIC FORMULA

x =  \frac{-b \pm \sqrt{b^{2} - 4ac}   }{2a}

Now, b^{2}  - 4ac = 1^{2}  - 4 (11) (5) = 1 - 220 = -219

Now as discriminant D < 0, then the roots are imaginary and distinct.

So, roots are x = \frac{-1 + \sqrt{(-219)} }{22} , \space  x = \frac{-1 - \sqrt{(-219)} }{22}

These are the two roots of the given equation.

3 0
3 years ago
Express ✓ – 75 in its simplest form.
timofeeve [1]

Step-by-step explanation:

The correct answer is 5i\sqrt{3}

3 0
3 years ago
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