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tatuchka [14]
3 years ago
13

How to use implicit differentiation to find an equation of the tangent line?

Mathematics
1 answer:
Arada [10]3 years ago
5 0
The slope of the line is the dy/dx value every time it appears in the differential equation. By substituting values for x and y in the DE, the slope can be found for the tangent at a point. This is the value of m in y=mx+a. To find a, plug in the tangent point.
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Identify the means and the extremes in each of the following proportions.
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PLEASE HELP WILL MARK BRAINLIEST!!
noname [10]

Answer:

m∠A = 91°

m∠B = 146°

m∠C = 89°

m∠D = 34°

Step-by-step explanation:

  • If the four vertices of a quadrilateral lie on the edge of a circle, then this quadrilateral is called cyclic quadrilateral
  • In the cyclic quadrilateral each two opposite angles are supplementary (means the sum of their measures is 180°)
  • The sum of the measures of the interior angles of any quadrilateral is 360°

In quadrilateral ABCD

∵ A, B, C, And D lie on the circumference of the circle

∴ ABCD is a cyclic quadrilateral

∴ The sum of the measures of each opposite angles is 180°

∵ ∠A and ∠C are opposite angle in the cyclic quadrilateral ABCD

∴ m∠A + m∠C = 180°

∵ m∠A = (2x + 3)°

∵ m∠C = (2x + 1)°

- Add them and equate the answer by 180

∴ (2x + 3) + (2x + 1) = 180

- Add the like terms in the left hand side

∴ 4x + 4 = 180

- Subtract 4 from both sides

∴ 4x = 176

- Divide both sides by 4

∴ x = 44

Substitute the value of x in the expressions of angle A, C, D

∵ m∠A = 2(44) + 3 = 88 + 3

∴ m∠A = 91°

∵ m∠C = 2(44) + 1 = 88 + 1

∴ m∠C = 89°

∵ m∠D = x - 10

∴ m∠D = 44 - 10

∴ m∠D = 34°

- ∠B and ∠D are opposite angles in the cyclic quadrilateral ABCD

∴ m∠B + m∠D = 180°

∴ m∠B + 34 = 180

- Subtract 34 from both sides

∴ m∠B = 146°

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