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tatuchka [14]
3 years ago
13

How to use implicit differentiation to find an equation of the tangent line?

Mathematics
1 answer:
Arada [10]3 years ago
5 0
The slope of the line is the dy/dx value every time it appears in the differential equation. By substituting values for x and y in the DE, the slope can be found for the tangent at a point. This is the value of m in y=mx+a. To find a, plug in the tangent point.
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If a car can go 300 miles on 12 gallons, how far can it go on 1 gallon
insens350 [35]

Answer:

The car can go 25 miles on 1 gallon.

Step-by-step explanation:

300 divided by 12 equals 25. Therefore, the car can go 25 miles on 1 gallon.

8 0
3 years ago
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PLEASE GIVE ME A VALID ANSWER IM GIVING ALOT OF POINTS!
seraphim [82]

Answer:

Step-by-step explanation: It is 1/2 of 14 = 7 hours to the moot

And plug in 7 hours to the equation  4*7+14*7=126 divide that by 2 and the distance is 63

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3 years ago
PLSSS HELP ME i need helppp
kozerog [31]
Answer: 12.56



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3 0
3 years ago
Help please! <br><br> Find x
zloy xaker [14]

Answer:

6√2

Step-by-step explanation:

A 45 45 90 right triangle, so ratio of leg : leg: hypotenuse = a: a : a√2 (a = value of leg)

Given: leg = 6

So the ratio of leg : leg: hypotenuse = 6 : 6 : 6 √2

Answer:

x = 6√2

6 0
3 years ago
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A couple quick algebra 1 questions for 50 points!
kkurt [141]

Answer:

Question 6) Neither (Not an inverse variation)

Question 7) Inverse variation

Question 8) Inverse variation

Step-by-step explanation:

These are the two formulas we need to know prior to solving the question.

Direct variation: c times x

Inverse variation: c times 1/x --> c/x

- Here, c is the constant

6. y = x + 7

This is neither. It is not in the form of a direct, or inverse variation, so it does not belong in any category.

7. 14 = xy

This equation is an inverse variation.

xy = 14

y = 14/x

14 is the constant, and the format is the same as for an inverse variation.

8. x = -8/y

This equation is an inverse variation.

yx = -8

y = -8/x

-8 is the constant, and the format is the same as for an inverse variation.

So we can conclude that questions 7 and 8 is an inverse variations, while question 6 isn't.

6 0
2 years ago
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