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tatuchka [14]
4 years ago
13

How to use implicit differentiation to find an equation of the tangent line?

Mathematics
1 answer:
Arada [10]4 years ago
5 0
The slope of the line is the dy/dx value every time it appears in the differential equation. By substituting values for x and y in the DE, the slope can be found for the tangent at a point. This is the value of m in y=mx+a. To find a, plug in the tangent point.
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625 with -3/4 exponent
MrRa [10]

Answer:

I believe it would be 1/125 or 0.008 depending on which form you need it in

5 0
3 years ago
Translate the following statement to an inequality.
Aliun [14]
The answer should be x≤7
6 0
3 years ago
Read 2 more answers
I really need help on my Study Island. If you are correct, I will give you Brainliest. Thanks!
yarga [219]

Answer:

20

Step-by-step explanation:

You need to create two equations for each company and then set them equal to each other. The keywords base fee means you will pay this amount regardless, so this amount stays constant and it will be the constant in the equation.  The other keyword is per. Per will link the variable with the coefficient.

The first equation for company M:

y = 12x + 60

The second equation for company N:

y = 9x + 120

Set the equations equal to each other.

9x + 120 = 12x + 60

Solve for x. I am going to subtract 9x from both sides first.

9x - 9x + 120 = 12x -9x +60

120 = 3x +60

Now, I will subtract 60 from both sides.

120 - 60 = 3x + 60 - 60

60 = 3x

Finally, I will divide both sides by 3

60/3 = 3x/3

x = 20

20 is how many guests it will take for the total cost to be the same.

5 0
2 years ago
Billy was folding laundry. She folded 40 shirts from 7:20 to 7:40. When she finishes folding all the shirts, she
solniwko [45]

Answer:

20 min for 40 shirts, two shirts a minute

7 0
3 years ago
Ryan flew from Wiley Post to Ponca City and back. Ryan maintained an average rate of 450 mph going to Ponca City and an average
Reil [10]
The answer is B, and here's why.  Set up a table for "there" and "back" and use the distance = rate * time formula, like this:
               d             r            t
there       d           450         t
back        d           400        1-t

Let me explain this table to you.  The distance is d, we don't know what it is, that's what we are actually looking for.  We only know that if we go somewhere from point A to point B, then back again to point A, the distance there is the same as the distance back.  Hence, the d in both spaces.  There he flew 450 mph, back he flew 400 mph.  If the total distance was 1 hour, he flew an unknown time there and one hour minus that unknown time back.  For example, if he flew for 20 minutes there, one hour minus 20 minutes means that he flew 60 minutes - 20 minutes = 40 minutes back.  See? Now, because the distance there = the distance back, we can set the rt in both equal to each other.  If d = rt there and d = rt back and the d's are the same, then we can set the rt's equal to each other.  450t = 400(1-t) and
450t = 400 - 400t and 850t = 400.  Solve for t to get t = .47058.  Now, t is time, not the distance and we are looking for distance. So multiply that t value by the rate (cuz d = r*t) to get that the distance one way is
d = 450(.470580 and d = 211. 76 or, rounded like you need, 212.
4 0
3 years ago
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