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4 years ago

13

How to use implicit differentiation to find an equation of the tangent line?

1 answer:

Arada [10]4 years ago

5 0

The slope of the line is the dy/dx value every time it appears in the differential equation. By substituting values for x and y in the DE, the slope can be found for the tangent at a point. This is the value of m in y=mx+a. To find a, plug in the tangent point.

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I need help with this question ?<br><br><br> Plsss

Anestetic [448]

Answer:

x=0

Step-by-step explanation:

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3 years ago

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PLEASE HELP QUICKLY!! I WILL MARK BRAINLIEST!!

Debora [2.8K]

Answer:

6 and 2/3

Step-by-step explanation:

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3 years ago

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Reil [10]

<u>Answer:</u>

x = 5.00 cm

<u>Step-by-step explanation:</u>

• area of the rectangle = $x$ x $(x + 1)$

= $x^2 + x$

• area of the circle = π r²

= $\frac{22}{7}$ x $(x + 2)^2$

= $\frac{22}{7}$ x $(x^2 + 4x + 4)$

∴ $x^2 + x$ + $\frac{22}{7}$ x $(x^2 + 4x + 4) = 184$

⇒ $x^2 + x$ + $\frac{22}{7} x^2 \space\ + \space\ \frac{88}{7} x \space\ + \space\ \frac{88}{7} = 184$

⇒ $\frac{29}{7}x^2 \space\ + \space\ \frac{95}{7}x \space\ - \frac{1200}{7} = 0$

• Using quadratic formula, where

a = $\frac{29}{7}$

b = $\frac{95}{7}$

c = $\frac{-1200}{7}$ ,

$x=\frac{-b \pm \sqrt{b^2-4c}}{2}$

$x = \frac{-\frac{95}{7}\pm \sqrt{(\frac{95}{7})^2 - 4(\frac{29}{7})(\frac{-1200}{7} ) } }{2(\frac{29}{7})}$

$x = 5.00 \space\ \space\ \space\ or \space\ \space\ \space\ x = -8.28$

As length (x) cannot be a negative number,

x = 5.00 cm

7 0

2 years ago

Help me please thank you

docker41 [41]

After I read the equation, I remembered that anything to the power of 1 is itself. so f(x)=2-9

2-9= -7

therefore, f(x)= -7

if x=1, then the f(x) must be Y

<u><em>therefore, your answer should be y= -7</em></u>

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3 years ago

What is a function???

boyakko [2]

A function in math is a relationship or expression involving one or more variables.

3 0

3 years ago