Answer:
$0.21
Step-by-step explanation:
Let x be the amount of money earned per hour before raise and y be amount of money earned per hour after raise.
We have been given that before raise he worked 38 hours and earned $220. We can represent this information as:
We are also told that the next week, he received a raise. After raise he worked 30 hours and made $180. We can represent this information as:
.
Let us solve for x and y.
Therefore, before raise Mike earned $5.7894 per hour.


Therefore, after raise Mike earned $6 per hour.
Now let us subtract 5.7894 from 6 to find Mike's raise.


Therefore, amount of Mike's raise to the nearest cent is $0.21.
First, find the area of the base (the triangle) and then multiply it by the height
to find the area of the triangle you need to know the height. cut the triangle in half and you get a right triangle, from there you can use the Pythagorean theorem. remember since you cut the triangle in half you have to divide one of the sides by 2
a^2 + b^2 = c^2 (plug in known information)
a^2 + (7.5)^2 = (15)^2 (solve, first solve the exponents)
a^2 + 56.25 = 225 (subtract 56.25 on both sides)
a^2 = 168.75 (solve for a, put 168.75 under the square root)
then once you find the area multiply by the known height
Answer:
10 units
Step-by-step explanation:
LMNO is a square.
All sides of square are equal
MN = LM
3x + 1 = x + 7
3x - x = 7 - 1
2x = 6
x = 6/2
x = 3
LM = x + 7 = 3 + 7 = 10
LM = 10 units
Answer:
A Tourist Information Center is between a Bus Station and a Train Station. When mapped on a grid, the Tourist Information Center is
located at (15,2) and the Bus Station is located at (5,-10).
The Train Station is located at point?Texaco station. Suppose the next six cars that stop at any of these four station make their selection randomly and independently. Is x a discrete or a continuous random variable?. Explain what are the poss
Answer:
4 kg of sugar would contain
crystals.
Step-by-step explanation:
Given that 3kg of sugar contains 9 × 10⁸ crystals, let "x" represent the number of sugar crystals 4kg of sugar would contain.
Thus, set up a proportion as follows:
3 kg : 9 × 10⁸ = 4 kg : x

Solve for x. Cross multiply.



Divide both sides by 3


4 kg of sugar would contain
crystals.