Let the numbers be x and y
According to the data : xy=-15 and x+y=-7
xy=-15
x+y=-7
y=-7-x
x(-x-7)=-15
y=-7-x
-x^2-7x=-15
y=-7-x
x^2+7x-15=0
y=-7-x
x=(-7±sqrt(7*7+4*15))/2
y=-7-x
x=(-7±sqrt(109<span>))/2
</span>
Goes to two systems.
1)
y=-7-x
x=(-7+sqrt(109<span>))/2
</span>
y=-7+3.5-sqrt(109<span>))/2
</span>x=(-7+sqrt(109<span>))/2
</span>
y=-3.5-sqrt(109<span>))/2
</span>x=(-7+sqrt(109<span>))/2
</span>
2)
y=-7-x
x=(-7-sqrt(109<span>))/2
</span>
y=-7+3.5+sqrt(109))/2
x=(-7-sqrt(109))/2
y=-3.5+sqrt(109))/2
x=(-7-sqrt(109<span>))/2</span>
Answer:
Step-by-step explanation:
19.5
21 pages. you divide 147 by 7 and get 21 pages
7 = 14x - 42y
42y = 14x - 7
y = (14x - 7)/ 42
or we could write it as y = (1/3)x - 1/6
It is the fourth choice - 1/4.
There are five odd number out of the ten number they are choosing from.
The probability that Jason will choose an odd number is 5/10 = 1/2
The probability that Kyle will choose an odd number is 5/10 = 1/2
Multiply the two probabilities to get the probability of them choosing odd numbers.
1/2 * 1/2 = 1/4
