3 years ago

How to put 24/27 in simplest form

Mathematics

2 answers:

Brrunno [24]3 years ago

7 0

Divide 3 by both sides , 3/24 is 8 and 3/27 is 9

iogann1982 [59]3 years ago

5 0

Answer:

8/9

Step-by-step explanation:

divide both numerator and denominator by 3

therefore u get 8/9

You might be interested in

Emerson deposited $194 into the bank. What will the balance be if Emerson left the money there for 7 years with an interest rate

SOVA2 [1]

Answer:

You just have to round to the cent place to get your answer

Step-by-step explanation:

Hope it helped!

-Brainly User

4 0

3 years ago

Read 2 more answers

Simplify the remaining expression completely x^6y^4/xy^2

polet [3.4K]

Answer: x^5y^2

Step-by-step explanation:

6 0

2 years ago

Substitute t=3 and t=5 to determine if the two expressions are equivalent.

motikmotik

Answer:

because both sides are equal when substituted by 3 & 5

4 0

2 years ago

What is the square root of 16?

natulia [17]

square root of 16 would be 4

4 x 4 = 16

8 0

3 years ago

Read 2 more answers

Sin α = 21/29, α lies in quadrant II, and cos β = 15/17, β lies in quadrant I Find sin (α - β).

Sever21 [200]

$\sin(\alpha-\beta)=\sin\alpha\cos\beta-\cos\alpha\sin\beta$

$\sin\alpha=\dfrac{21}{29}\implies \cos^2\alpha=1-\sin^2\alpha=\dfrac{400}{841}$

Since $\alpha$ lies in quadrant II, we have $\cos\alpha$ , so

$\cos\alpha=-\sqrt{\dfrac{400}{841}}=-\dfrac{20}{29}$

$\cos\beta=\dfrac{15}{17}\implies\sin^2\beta=1-\cos^2\beta=\dfrac{64}{289}$

$\beta$ lies in quadrant I, so $\sin\beta>0$ and

$\sin\beta=\sqrt{\dfrac{64}{289}}=\dfrac8{17}$

So

$\sin(\alpha-\beta)=\dfrac{21}{29}\dfrac{15}{17}-\left(-\dfrac{20}{29}\right)\dfrac8{17}=\dfrac{475}{493}$

8 0

3 years ago