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aniked [119]
3 years ago
7

A number divided by four is 271. What is the number?

Mathematics
2 answers:
Ainat [17]3 years ago
6 0

Answer:

1084

Step-by-step explanation:

271 x 4= 1084

laila [671]3 years ago
5 0

Step-by-step explanation:

N ÷ 4 = 271

N ÷ 4 * 4 = 271 * 4

N = 271 * 4

N = 1084

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What is the value of the expression shown below?
Ymorist [56]
(8 + [7+1] 2 ÷ 4 × 1) ÷ 2^4

Let's focus on what's in parentheses first.

8 + 8 × 2 ÷ 4 × 1
8 + 16 ÷ 4 × 1
8 + 4 × 1
8 + 4
12

Now, to what is outside the parentheses:

Because of the way it is written, you will do 12 ÷ 2 first.
12 ÷ 2^4
6^4

Answer: 1296
8 0
3 years ago
Read 2 more answers
12c+2d=48g. Solve for d. Step by step please
Daniel [21]

Answer:

d=24g-6c

Step-by-step explanation:

12c+2d=48g

2d=48g-12c

d=24g-6c

7 0
3 years ago
Find the measure of the arc or angle indicated. NO LINKS.​
Advocard [28]

9514 1404 393

Answer:

  10.  A) 120°

  11.  D) 40°

  12.  D) 54°

  13.  A) 101°

Step-by-step explanation:

The applicable rules of angles and arcs are ...

  • the whole is the sum of the parts
  • arcs of a circle total 360°
  • an inscribed angle intercepts an arc of twice its measure

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10) Angles C and L intercept the same arc (DE) so will have the same measure.

  15x = 16x -4

  4 = x . . . . . . . . add 4-15x

  arc DE = 2(15x) = 30(4) = 120 . . . degrees

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11) Arc VW is twice the measure of angle X, so ...

  9x +8 = 2(5x)

  8 = x . . . . . . . . . subtract 9x

  ∠VXW = 5x = 5(8) = 40 . . . degrees

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12) Arc EFG is twice the measure of angle W, so ...

  70° +FG = 2(88°)

  FG = 106° . . . . . . . . . subtract 70°

Arc FGW is twice the measure of angle E, so ...

  106° +GW = 2(80°)

  GW = 54° . . . . . . . . . . subtract 106°

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13) Arc ST is twice the measure of angle R. The sum of arcs is 360°.

  RS +ST +TR = 360°

  119° +2(70°) +TR = 360°

  TR = 101° . . . . . . . . subtract 259°

5 0
3 years ago
Read 2 more answers
Find four consecutive integers such that the sum of the first and third is eight les than twice the sum of the second and fourth
lyudmila [28]
X, x+1, x+2, x+3 are 4 consecutive integers

2(x + x+2) = 5(x+3) - 26
2(2x+2) = 5(x+3) - 26
4x + 4 = 5x + 15 - 26
4x + 4 = 5x - 11
15 = x
15, 16, 17, 18

x, x+2, x+4 consecutive even integers
2(x+4)+11 = x + 9
2x + 8 + 11 = x + 9
2x + 19 = x + 9
x = -10
-10, -8, -6
5 0
2 years ago
How many terms of the series of - 3+0+3+6+9+...are needed to give a sum of 105?​
dolphi86 [110]

Answer:

10

Step-by-step explanation:

Remember that the formula for the sum of an arithmetic series is:

S=\frac{k}{2}(a+x_k)

Where k is the number of terms, a is the initial term, and x_k is the last term of the series.

We essentially want to find k, the number of terms, given that the sum S is equal to 105. So, substitute 105 into our equation:

105=\frac{k}{2}(a+x_k)

To do so, we need to final term x_k. We don't know what it is yet, but that doesn't matter. All we need to do is to write it in terms of k. First, remember that the standard form for the explicit formula of an arithmetic sequence is:

x_n=a+d(n-1)

Where a is the first term, d is the common difference, and n is the nth term.

From our sequence, we can see that the first term is -3.

Also, we can determine that our common difference is +3, since each subsequent term is 3 <em>more</em> than the previous one. -3+3 is 0, 0+3 is 3, 3+3 is 6, and so on.

Therefore, our explicit formula is:

x_n=-3+3(n-1)

Therefore, our final term, x_k, will be if we substitute k for n. So, we can acquire the equation:

x_k=-3+3(k-1)

Now that we know what x_k is, we can substitute that into our original equation:

105=\frac{k}{2}(a+x_k)

Substitute the equation into x_k. Also, let's substitute -3 (our first term) for a. So:

105=\frac{k}{2}(-3+(-3+3(k-1)))

And now, all we have to do is to solve for k.

First, distribute the 3:

105=\frac{k}{2}(-3+(-3+3k-3))

Add within the parentheses:

105=\frac{k}{2}(3k-9)

Multiply both sides by 2. This removes the fraction on the right:

210=k(3k-9)

Distribute. We will get a quadratic:

210=3k^2-9k

So, let's solve for k. Let's divide everything by 3:

70=k^2-3k

Subtract 70 from both sides:

0=k^2-3k-70

Factor. We can use -10 and 7. So:

0=(k-10)(k+7)

Zero Product Property:

k-10=0\text{ or } k+7=0

Solve for k for each equation:

k=10\text{ or } k=-7

-7 doesn't make sense (we can't have -7 terms). Remove that solution. So, we are left with:

k=10

Therefore, the number of terms we have in our series for our sum to be 105 is 10.

And we're done!

4 0
3 years ago
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