What is the quick key to highlighting a column?

______ is the software that blocks a user from being able to access your computer.

antiseptic1488 [7]

The answer is firewall. It is a network security device that observes inbound and outbound network traffic and chooses whether to allow or block specific traffic based on a well-defined set of security rules. Firewalls have been a first line of protection in network security for over 25 years. The firewall present a barrier between measured and secured internal networks that can be trusted and untrusted outside networks, for example the Internet. A firewall can be software, hardware, or even both.

8 0

3 years ago

There will be 10 numbers stored contiguously in the computer at location x 7000 . Write a complete LC-3 program, starting at loc

Artist 52 [7]

Answer:

The LC-3 (Little Computer 3) is an ISA definition for a 16-bit computer. Its architecture includes physical memory mapped I/O via a keyboard and display; TRAPs to the operating system for handling service calls; conditional branches on N, Z, and P condition codes; a subroutine call/return mechanism; a minimal set of operation instructions (ADD, AND, and NOT); and various addressing modes for loads and stores (direct, indirect, Base+offset, PC-relative, and an immediate mode for loading effective addresses). Programs written in LC-3 assembler execute out of a 65536 word memory space. All references to memory, from loading instructions to loading and storing register values, pass through the get Mem Adr() function. The hardware/software function of Project 5 is to translate virtual addresses to physical addresses in a restricted memory space. The following is the default, pass-through, MMU code for all memory references by the LC-3 simulator.

unsigned short int get Mem Adr(int va, int rwFlg)

{

unsigned short int pa;

// Warning: Use of system calls that can cause context switches may result in address translation failure

// You should only need to use gittid() once which has already been called for you below. No other syscalls

// are necessary.

TCB* tcb = get TCB();

int task RPT = tcb [gettid()].RPT;

pa = va;

// turn off virtual addressing for system RAM

if (va < 0x3000) return &memory[va];

return &memory[pa];

} // end get MemAdr

Simple OS, Tasks, and the LC-3 Simulator

We introduce into our simple-os a new task that is an lc3 Task. An lc3 Task is a running LC-3 simulator that executes an LC-3 program loaded into the LC-3 memory. The memory for the LC-3 simulator, however, is a single global array. This single global array for memory means that alllc3 Tasks created by the shell use the same memory for their programs. As all LC-3 programs start at address 0x3000 in LC-3, each task overwrites another tasks LC-3 program when the scheduler swaps task. The LC-3 simulator (lc3 Task) invokes the SWAP command every several LC-3 instruction cycles. This swap invocation means the scheduler is going to be swapping LC-3 tasks before the tasks actually complete execution so over writing another LC-3 task's memory in the LC-3 simulator is not a good thing.

You are going to implement virtual memory for the LC-3 simulator so up to 32 LC-3 tasks can be active in the LC-3 simulator memory without corrupting each others data. To implement the virtual memory, we have routed all accesses to LC-3 memory through a get Mem Adr function that is the MMU for the LC-3 simulator. In essence, we now have a single LC-3 simulator with a single unified global memory array yet we provide multi-tasking in the simulator for up to 32 LC-3 programs running in their own private address space using virtual memory.

We are implementing a two level page table for the virtual memory in this programming task. A two level table relies on referring to two page tables both indexed by separate page numbers to complete an address translation from a virtual to a physical address. The first table is referred to as the root page table or RPT for short. The root page table is a fixed static table that always resides in memory. There is exactly one RPT per LC-3 task. Always.

The memory layout for the LC=3 simulator including the system (kernel) area that is always resident and non-paged (i.e., no virtual address translation).

The two figures try to illustrate the situation. The lower figure below demonstrates the use of the two level page table. The RPT resident in non-virtual memory is first referenced to get the address of the second level user page table or (UPT) for short. The right figure in purple and green illustrates the memory layout more precisely. Anything below the address 0x3000 is considered non-virtual. The address space is not paged. The memory in the region 0x2400 through 0x3000 is reserved for the RPTs for up to thirty-two LC-3 tasks. These tables are again always present in memory and are not paged. Accessing any RPT does not require any type of address translation.

The addresses that reside above 0x3000 require an address translation. The memory area is in the virtual address space of the program. This virtual address space means that a UPT belonging to any given task is accessed using a virtual address. You must use the RPT in the system memory to keep track of the correct physical address for the UPT location. Once you have the physical address of the UPT you can complete the address translation by finding the data frame and combining it with the page offset to arrive at your final absolute physical address.

A Two-level page table for virtual memory management.

x7000 123F x7000 0042

x7001 6534 x7001 6534

x7002 300F x7002 300F

x7003 4005 after the program is run, memory x7003 4005

x7004 3F19

7 0

2 years ago

Read 2 more answers

Problem 2 Write a method that (a) returns an int[] , (b) takes in two sorted arrays (in descending order) and (c) returns an int

Galina-37 [17]

Answer:

Following are the Program in the Java Programming Language.

//define class

public class Main

{

//define function to merge and sort array

public static int[] sort_Array(int[] a, int[] b)

{

//set integer variable and initialize values

int x = 0, y = 0, k = 0, num = 0;

int n = a.length;

int n1 = b.length;

//set integer type array

int[] ar = new int[n+n1];

//set while loop

while (x<n && y <n1)

{

num++;

//set if conditional statement

if (a[x] > b[y])

ar[k++] = a[x++];

else

ar[k++] = b[y++];

num++;

}

//set the while loop

while (x < n)

{

num++;

ar[k++] = a[x++];

}

//set the while loop

while (y < n1)

{

num++;

ar[k++] = b[y++];

}

//print the total compares done

System.out.println("Number of compares done: " + n);

//return array

return ar;

}

//define main method

public static void main(String[] args)

{

//declaration and the initialization of array

int[] a = new int[]{18,16, 15, 6, 2};

int[] b = new int[]{13, 12, 11, 7, 1};

int[] ar;

//call function

ar = sort_Array(a, b);

//print message

System.out.println("\nThe resultant array is: \n");

//set for loop to print array

for(int x=0; x<ar.length; x++)

{

System.out.print(ar[x] + " ");

}

<u>Output</u>:

Number of compares done: 5

The resultant array is:

18 16 15 13 12 11 7 6 2 1

Explanation:

Here, we define a class "Main" inside the class, define a function "sort_Array()"and pass two integer type array argument "a" and "b".

Set four integer type variables "x", "y", "k", and "num" and initialize them to 0.
Set two integer type array "n", "n1" and initialize them the length of the array then, set integer type array variable "ar".
Set the while loop then, set if conditional statement then, agin set while loop to sort array in descending order.
Then, print the number of compares and return the value of the variable "ar".

Finally, define the main method inside it, we set two integer type array variable and initialize elements in them then, set the for loop to print the sorted elements of the array.

4 0

2 years ago

A campfire is a good source of heat and light on a cool night. The energy that is released when firewood is burned comes from th

Makovka662 [10]

Chemical reactions in the material used to make matches, and the cardboard... so hope this helps :)

NOTE: im not to good at this stuff so i rlllllly hope it helps

3 0

3 years ago

A semiconductor kit is used on a

iragen [17]

The correct answer is PSC motor.

If you need more help, you can check on quizlet, I learnt about ecd from there lol

5 0

2 years ago