Answer:
Go to remove a background website
Explanation:
Answer:
Check the explanation
Explanation:
public class EnhancedForExample {
public static void main(String[] args) {
int[] arr = {4, 2, 9, 1, 5, 7};
for(int num : arr) {
System.out.println(num);
}
}
}
Kindly check the attached image below for the code output.
Answer:
Following is given the solution of your question as required.
All the necessary descriptions are given in form of comments,
Sample output are also shown.
I hope it will help you!
Explanation:
Answer:
have the same SSID but different channels
Explanation:
Based on the information provided within the question it can be said that the best option to accomplish this would be to have the same SSID but different channels. This would maintain the users connected to the same network name (SSID) but still be able to roam and jump from one access point to the other.
Answer:
from socket import *
hostname = input('Enter the host to be scanned: ')
ip_add = gethostbyname(hostname)
connections = [ ]
for i in range(133, 136):
s = socket(AF_INET, SOCK_STREAM)
conn = s.connect_ex((ip_add, i))
print(conn)
connections.append(conn)
if 0 in connections:
print ('Host is online')
s.close()
else:
print ('system is unreachable')
Explanation:
The python source code above scans for all the available range of ports in the provided hostname, if any port is available, the host is online else the program print the error message "system is unreachable.