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cupoosta [38]
3 years ago
9

How do you solve x-6>7=

Mathematics
1 answer:
alexandr402 [8]3 years ago
4 0

By subtracting and

Dividing

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(3x+1/2)+(7x-41/2)what is the answer
Svetach [21]

Answer:

10x + 5 (or if thats a 41/2 then) 10x + 42

Step-by-step explanation:

3x + 1/2 + 7x - 4 1/2

10x + 5

or if thats a 41/2

3x + 1/2 + 7x - 41/2

10x + 42

3 0
3 years ago
PLEASEEEE HELP ME!!
emmainna [20.7K]

Answer:

A) 5*(-6)*(-1)

-30*(-1)

30

B) -6+(-1)

-6-1

-7

C) 5/(-1)

-5

7 0
4 years ago
Which of the following is an odd function?
Komok [63]

Given:

f(x)=x^{3}+5 x^{2}+x

f(x)=\sqrt{x}

f(x)=x^{2}+x

f(x)=-x

To find:

The odd function.

Solution:

If f(-x) = -f(x), then the function is odd.

If f(-x) = f(x), then the function is even.

Option A: f(x)=x^{3}+5 x^{2}+x

Substitute x = -x

f(-x)=(-x)^{3}+5 (-x)^{2}+(-x)

          =-x^3+5x^2-x

          =-(x^3-5x^2+x)

          ≠ - f(x)

It is not odd function.

Option B: f(x)=\sqrt{x}

Substitute x = -x

f(-x)=\sqrt{-x}

          =\sqrt{x} i   (Since \sqrt{-1} =i)

          ≠ - f(x)

It is not odd function.

Option C: f(x)=x^{2}+x

Substitute x = -x

f(-x)=(-x)^{2}+(-x)

          =x^2-x

          =-(-x^2+x)

          ≠ - f(x)

It is not odd function.

Option D: f(x)=-x

Substitute x = -x

f(-x)=-(-x)

          =-f(x)

It is odd function.

Therefore, f(x) = -x is an odd function.

5 0
3 years ago
Error bars on four different data points are shown below.
Verdich [7]

I think it is point 3. Hope that helps

7 0
3 years ago
Read 2 more answers
HELP ITS A QUIZ<br><br><br> (15÷3)2 +9÷3
andrew-mc [135]
Answer=13
Hope this helps
3 0
3 years ago
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