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3 years ago

Which interval is the solution to (x+3)^2<(or equal to) 25?

2 answers:

8 0

First of all, you can graph any equation into Desmos. Just type in an equation and it will graph it correctly.

To find the interval (how much the graph covers), graph the equation then look at what x-values the function covers.

As you can see the function covers everything from -8 to 2 on the x-axis.

Therefore, the interval is [-8,2]

The interval is in brackets because it includes both -8 and 2 in the function.

If it did not include -8 or 2 but everything in between the interval would be (-8,2)

olga2289 [7]3 years ago

5 0

(x+3)^2<=25
x+3<=5
x<=3
using x=-8, (-8+3)^2=25
we have [-8,2]
so A.

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3 years ago

CD is perpendicular to AB and passes through point C5, 12).

Aleksandr-060686 [28]

Answer:

x intercept of CD = 17

Step-by-step explanation:

We are given a line AB with its end coordinates. and Another line segment CD which is perpendicular to AB. We have the coordinates of C , and we are asked to find the x intercept of line CD.

For that we need to find the equation of CD

we have coordinates of C , and hence if we have slope of CD we can find equation of CD

Slope of CD can be determine with the help of slope of AB as CD⊥ AB

So, the slope of CD $mCD = -\frac{1}{mAB}$

Hence we start from determining slope of AB

slope is given as

$m= \frac{y_2-y_1}{x_2-x_1}$

$m= \frac{14-(-3)}{7-(-10)}=\frac{17}{17}=1$

Hence $mAB=1$

There fore $mCD=-1$

(∵ Product of Slopes of two perpendicular lines is always -1)

Now we find the equation of CD with the help of slope -1 and coordinates of C(5,12)

$m=\frac{y-y_1}{x-x_1}$

$-1=\frac{y-12}{x-5}$

$-x+5=y-12$

$y=-x+17$

Hence we have our equation , now in order to find the x intercept we keep y = 0 in it and solve for x

$0=-x+17$

$x=17$

Hence the x intercept is 17

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3 years ago

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rjkz [21]

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2x^2 - 5x + 3

Now we can put -3 into the equation and solve.

2(-3)^2 - 5(-3) + 3

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3 years ago