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elena-14-01-66 [18.8K]
3 years ago
8

A recipe calls for their ratio of sugar to flower to be 10.3. If you use 70 ounces of sugar how many ounces of flour would you n

eed to use?
Mathematics
1 answer:
bulgar [2K]3 years ago
6 0

This means that for every 10 of whatever measurement of sugar there will be 3 of that measurement of flour

70 oz of sugar / 10 = 7

3 (ratio of flour) times 7 = 21

21

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Which ordered pair is not a solution of the equation 3x+2y=-10? A: (-4,1) B: (-5,4) C:(2,-8)
Angelina_Jolie [31]
Plug in the values and see which ones do not fi:-

. A      3(-4) + 2(1) =  -10

that fits  so it must be B, C or D.
4 0
3 years ago
Which expression is equivalent to 6m+(m-2)(m+7)+3
Vika [28.1K]

Answer:

m^{2} + 11m - 11

Step-by-step explanation:

6m+(m-2)(m+7)+3  =   6m   +  [ m*m - 14 -2m + 7m]  + 3

=  6m  + mm - 14 + 5m  + 3

=  mm + 11m - 11

6m+(m-2)(m+7)+3   = m^{2} + 11m - 11

5 0
4 years ago
A laboratory scale is known to have a standard deviation (sigma) or 0.001 g in repeated weighings. Scale readings in repeated we
weqwewe [10]

Answer:

99% confidence interval for the given specimen is [3.4125 , 3.4155].

Step-by-step explanation:

We are given that a laboratory scale is known to have a standard deviation (sigma) or 0.001 g in repeated weighing. Scale readings in repeated weighing are Normally distributed with mean equal to the true weight of the specimen.

Three weighing of a specimen on this scale give 3.412, 3.416, and 3.414 g.

Firstly, the pivotal quantity for 99% confidence interval for the true mean specimen is given by;

        P.Q. = \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \bar X = sample mean weighing of specimen = \frac{3.412+3.416+3.414}{3} = 3.414 g

            \sigma = population standard deviation = 0.001 g

            n = sample of specimen = 3

            \mu = population mean

<em>Here for constructing 99% confidence interval we have used z statistics because we know about population standard deviation (sigma).</em>

So, 99% confidence interval for the population​ mean, \mu is ;

P(-2.5758 < N(0,1) < 2.5758) = 0.99  {As the critical value of z at 0.5% level

                                                            of significance are -2.5758 & 2.5758}

P(-2.5758 < \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } < 2.5758) = 0.99

P( -2.5758 \times {\frac{\sigma}{\sqrt{n} } } < {\bar X - \mu} < 2.5758 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.99

P( \bar X-2.5758 \times {\frac{\sigma}{\sqrt{n} } } < \mu < \bar X+2.5758 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.99

<u>99% confidence interval for</u> \mu = [ \bar X-2.5758 \times {\frac{\sigma}{\sqrt{n} } } , \bar X+2.5758 \times {\frac{\sigma}{\sqrt{n} } } ]

                                             = [ 3.414-2.5758 \times {\frac{0.001}{\sqrt{3} } } , 3.414+2.5758 \times {\frac{0.001}{\sqrt{3} } } ]

                                             = [3.4125 , 3.4155]

Therefore, 99% confidence interval for this specimen is [3.4125 , 3.4155].

6 0
3 years ago
Please help as soon as possible <br>it's due tomorrow ​
erma4kov [3.2K]

Answer:

378 cm^3

Step-by-step explanation:

V = Bh = l * w * h

since the Base B is 54 (l*w), multiply by 7 to find volume

54 * 7 = 378

7 0
3 years ago
?÷2/3 = 3/4<br><br> 10 POINTS!!!
FromTheMoon [43]
The answer is 1/2. Multiply 3/4 by 2/3.
5 0
4 years ago
Read 2 more answers
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