Answer:
Step-by-step explanation:
Total Weight = 2½ + 1⅓ + 2
= 5/2 + 4/3 + 2
= 15/6 + 8/6 + 12/6
= 35/6
= 5⅚ pounds
I assume you mean squared? 16r^6^2 YOUR FINAL ANSWER= 16r^256
To find the answer, we can use the Pythagoras theorem, where:
![\sqrt{a^{2}+ b^{2} } =c^{2}](https://tex.z-dn.net/?f=%5Csqrt%7Ba%5E%7B2%7D%2B%20b%5E%7B2%7D%20%7D%20%3Dc%5E%7B2%7D)
Where a and b is the side length and c is the diagonal.
In this case:
![\sqrt{56^{2} +56^{2} } \\ =\sqrt{6272} \\ =79.19596... \\ =79.2(correct to 3 sig. fig.)](https://tex.z-dn.net/?f=%5Csqrt%7B56%5E%7B2%7D%20%2B56%5E%7B2%7D%20%7D%20%3C%2Fp%3E%3Cp%3E%5C%5C%20%3D%5Csqrt%7B6272%7D%20%5C%5C%20%3D79.19596...%20%5C%5C%20%3D79.2%28correct%20to%203%20sig.%20fig.%29)
Therefore, the answer is 79.2cm
Hope it helps!
Answer:
![17\ \text{hours and}\ 15\text{ minutes}](https://tex.z-dn.net/?f=17%5C%20%5Ctext%7Bhours%20and%7D%5C%2015%5Ctext%7B%20minutes%7D)
Step-by-step explanation:
The function is
![-4x+3y=21](https://tex.z-dn.net/?f=-4x%2B3y%3D21)
Where
x = Time in hours
y = Velocity in kilometers per hour
Here y = 30 km/hr
![-4x+3y=21\\\Rightarrow x=\dfrac{3y-21}{4}\\\Rightarrow x=\dfrac{3\times 30-21}{4}\\\Rightarrow x=\dfrac{69}{4}\\\Rightarrow x=17.25\ \text{hours}=17\ \text{hours and}\ 15\text{ minutes}](https://tex.z-dn.net/?f=-4x%2B3y%3D21%5C%5C%5CRightarrow%20x%3D%5Cdfrac%7B3y-21%7D%7B4%7D%5C%5C%5CRightarrow%20x%3D%5Cdfrac%7B3%5Ctimes%2030-21%7D%7B4%7D%5C%5C%5CRightarrow%20x%3D%5Cdfrac%7B69%7D%7B4%7D%5C%5C%5CRightarrow%20x%3D17.25%5C%20%5Ctext%7Bhours%7D%3D17%5C%20%5Ctext%7Bhours%20and%7D%5C%2015%5Ctext%7B%20minutes%7D)
The particle will reach 30 km/hr after
.