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Vika [28.1K]
3 years ago
11

Omer selects

Mathematics
1 answer:
Stels [109]3 years ago
3 0

Answer:

3. .75 :) your welcome I did awesome

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Please look for the question in the picture.
Korvikt [17]

Answer:

Step-by-step explanation:

B

whether the negative sign is next to the fraction bar or next to the numerator, it doesnt matter.

A results in the last number being different from the one in the question.

answer is B

6 0
2 years ago
Solve the inequality for x.<br><br> 2x +3 &lt; -13
zubka84 [21]

Answer:-8

Step-by-step explanation:

3 0
3 years ago
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Help asappppp? i’m having trouble on wat the 1/4 point is
blagie [28]

Answer:

  (-14, 5.5)

Step-by-step explanation:

Perhaps the easiest way to find the 1/4 point is to find (x, y), then find the midpoint between that and M.

  (x, y) = 2M -(13, 25) = 2(-5, 12) -(13, 25) = (-23, -1)

Then the 1/4 point is ...

  ((-23, -1) +M)/2 = ((-23, -1) +(-5, 12))/2 = (-28, 11)/2 = (-14, 5.5)

_____

If we call the end points A(x, y) and B(13, 25), then we know ...

  M = (A+B)/2

  A = 2M -B . . . . we'll need this in a bit

and the 1/4 point Q is such that ...

  (Q -A)/(B -A) = 1/4

  4Q -4A = B -A . . . . cross multipliy

  Q = (B +3A)/4 = (B +3(2M -B))/4 = (6M -2B)/4 . . . . solve for Q

  Q = (3M -B)/2 . . . . reduce the fractions

  Q = (3(-5, 12) -(13, 25))/2 = (-28, 11)/2 = (-14, 5.5) . . . as above

6 0
3 years ago
A roll of ribbon was 12 meters long. Diego cut 9 pieces of ribbon that were 0.4 meters each to tie some presents. He then used t
Alex777 [14]

Answer:

8.4 meters of ribbon left and 14 wreaths made

Step-by-step explanation:

9 * 0.4 = 3.6 meters used for presents

12 - 3.6 = 8.4 meters left for wreaths

8.4 / 0.6 = 14 wreaths

4 0
3 years ago
Read 2 more answers
Find S5 for a geometric series for which a1=81 and r=1/9.
Minchanka [31]

ANSWER

S_5=91\frac{10}{81}




EXPLANATION


The sum of the first n terms of a geometric sequence is given by;


S_n=\frac{a_1(1-r^n)}{1-r} ,-1


Where n, is the number of terms and a_1 is the first term.


When n=5, we have a_1=81, we get;


S_5=\frac{81(1-(\frac{1}{9})^5)}{1-\frac{1}{9}}


S_5=\frac{81(1-\frac{1}{59049})}{1-\frac{1}{9}}


S_5=\frac{81(\frac{59048}{59049})}{\frac{8}{9}}




S_5=\frac{7381}{81}


S_5=91\frac{10}{81}




6 0
3 years ago
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