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2 years ago

How many millimeters are there in 4.72 meters?

Mathematics

1 answer:

diamong [38]2 years ago

7 0

Answer:

4,720 millimeters

Step-by-step explanation:

4.72

4,720

472

4,7 so on

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a company that manufactures bicycles has a fixed cost of $80,000. it costs $100 to produce each bicycle. the total cost for the

frez [133]

C(x) = 80000 + 100x is the total cost as function of number of cycles produced

C(90) = 89000 and it costs $ 89000 to produce 90 bicycles

Solution:

Given that, company that manufactures bicycles has a fixed cost of $80,000

Fixed cost = $ 80,000

Let x be the number of cycles produced

Let C(x) be the total cost as function of number of cycles produced

It costs $100 to produce each bicycle

Variable cost = 100 x number of cycles produced

variable cost = 100x

The total cost for the company is the sum of its fixed cost and variable costs

total cost = fixed cost + variable cost

C(x) = 80000 + 100x

Thus total cost as function of "x" is found

Find and interpret C(90)

Substitute x = 90 in C(x)

C(90) = 80000 + 100(90)

C(90) = 80000 + 9000

C(90) = 89000

Thus it costs $ 89000 to produce 90 bicycles

3 0

2 years ago

Write the expression as a single logarithm

Yakvenalex [24]

$\log _a(6w+1)^{7} + \log _a(w+7)^{\frac{1}{5}} \\ \log _a(6w+1)^{7} + \log _a\sqrt[5]{(w+7)}\\\log _a((6w+1)^{7} (\sqrt[5]{(w+7)}))$

4 0

2 years ago

What is the area of a trapezoid if the base is 5, 17, 5 and height is 4

Snowcat [4.5K]

Answer:

Step-by-step explanation:

Trapezoid

Solve for area

A=44

a Base

b Base

h Height

7 0

3 years ago

The score of golfers for a particular course follows a normal distribution that has a mean of 73 and a standard deviation of 3.

Artemon [7]

Answer:

P(X $\geq$ 74) = 0.3707

Step-by-step explanation:

We are given that the score of golfers for a particular course follows a normal distribution that has a mean of 73 and a standard deviation of 3.

Let X = Score of golfers

So, X ~ N( $\mu=73,\sigma^{2}=3^{2}$ )

The z score probability distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = population mean = 73

$\sigma$ = standard deviation = 3

So, the probability that the score of golfer is at least 74 is given by = P(X $\geq$ 74)

P(X $\geq$ 74) = P( $\frac{X-\mu}{\sigma}$ $\geq$ $\frac{74-73}{3}$ ) = P(Z $\geq$ 0.33) = 1 - P(Z < 0.33)

= 1 - 0.62930 = 0.3707

Therefore, the probability that the score of golfer is at least 74 is 0.3707 .

3 0

3 years ago

(69 points!) Some1 please solve. (69 points!)

MAVERICK [17]

Answer:

for the second questio it is certainly The last choice D

Step-by-step explanation:

5 0

3 years ago