Answer:
Ur answer is #1 = A number line from negative 10 to 10 is shown with numbers labeled at intervals of 2. An arrow is shown from point 0 to negative 2. Another arrow points from negative 2 to 8.
Step-by-step explanation:
The arrow from 0 to -2 represents the initial "-2" of the problem. <em>Adding </em>-10 would put an arrow of length 10 from that point to the left to -12. However, you are <em>subtracting </em>-10, so that arrow is reversed and goes from -2 to +8.
Answer:
3/8
Step-by-step explanation:
Evaluate b - -1/8 + c where b = 2 and c = -7/4:
b - (-1)/8 + c = 2 - (-1)/8 - 7/4
Put 2 + 1/8 - 7/4 over the common denominator 8. 2 + 1/8 - 7/4 = (8×2)/8 + 1/8 + (2 (-7))/8:
(8×2)/8 + 1/8 - (7×2)/8
8×2 = 16:
16/8 + 1/8 - (7×2)/8
2 (-7) = -14:
16/8 + 1/8 + (-14)/8
16/8 + 1/8 - 14/8 = (16 + 1 - 14)/8:
(16 + 1 - 14)/8
16 + 1 = 17:
(17 - 14)/8
| 1 | 7
- | 1 | 4
| 0 | 3:
Answer: 3/8
Answer:
The simplified form is: 
Step-by-step explanation:
To simplify the expression given we, need to open the brackets, and if there is power term. Then we need to group all the like terms and then arrange in the descending order of powers of the given expression.
Now the expression that is given to us is:

Here we will simplify it by grouping the like terms, as follows:

So this is the required simplified form.
Answer:
Please be more clear and I might be able to help
Step-by-step explanation:
Answer:
$ 254.85
Step-by-step explanation:
Total amount invested = $ 560
Interest rate = r = 4.8% = 0.048
Time in years = t = 8 years
The formula for compound interest is:

Here,
A is the total amount accumulated after t years. P is the amount invested initially and n is the compounding periods per year. Since in this case compounding is done annually, n will be 1. Using the values in the above formula, we get:

Thus, the total amount accumulated after 8 years will be $ 814.85
The amount of interest earned will be:
Interest = Amount Accumulated - Principal Amount
Interest = $ 814.85 - $ 560 = $ 254.85
By the end of 8 years, $ 254.85 would be earned in interest.