Answer:
theres no problem
Step-by-step explanation:
In the "1s" place,
1₅ + 3₅ = 4₅
In the "5s" place,
2₅ + 4₅ = (6)₅ = (5 + 1)₅ = 10₅ + 1₅ = 11₅
In the "25s" place, we carry the leading 1 from the "5s" place,
3₅ + 3₅ + 1₅ = (7)₅ = (5 + 2)₅ = 10₅ + 2₅ = 12₅
In the "125s" place, we carry over the 1 again,
4₅ + 1₅ = (5)₅ = (5 + 0)₅ = 10₅ + 0₅ = 10₅
Putting everything together,
4321₅ + 343₅ = 10214₅
Sector area = (central angle / 360) * PI * radius^2
sector area = (1 / 6) * PI * 5^2
sector area =
<span>
<span>
<span>
13.08996939
</span>
</span>
</span>
sector area =
<span>
13.1 square inches
</span>
Answer:yes the answer is yezzzzzzzzzzzzzzzzzzzzzzz
Step-by-step explanation:
Take the linear coefients easy
11,-12, 7
5,12,-7
so
![\left[\begin{array}{ccc}11&-12&7\\5&12&-7\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D11%26-12%267%5C%5C5%2612%26-7%5Cend%7Barray%7D%5Cright%5D%20)
or you could do also