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soldi70 [24.7K]
3 years ago
7

PLEASE ANSWER I NEED HELP!

Mathematics
1 answer:
mash [69]3 years ago
8 0

Answer:

  25/2

Step-by-step explanation:

The marked angles are supplementary, so ...

  117 + (6x -12) = 180

  6x = 75 . . . . . . . . . . . subtract 105

  x = 25/2 . . . . . . . . . . divide by 6

You might be interested in
Students surveyed boys and girls separately to determine whether they wanted outdoor
vazorg [7]

Answer:

111 girls

Step-by-step explanation:

Given

Boys: Every 17 outdoor ≈ 20 indoor

Girls: 3:2 outdoor to indoor

First, we'll determine the ratio of outdoor to indoor for boys;

Recall that;

17 choose indoor while 20 choose outdoor;

The ratio of outdoor to indoor is;

20 : 17

Convert to fraction:

\frac{20}{17}

Let x represent number of boys that choose indoor when 85 boys chose outdoor;

The ratio of outdoor to indoor is;

x : 85

Convert to fraction

\frac{x}{85}

Equate both fractions

\frac{20}{17} = \frac{x}{85}

Multiply both sides by 85

85 * \frac{20}{17} = \frac{x}{85} * 85

85 * \frac{20}{17} = x

\frac{1700}{17} = x

100 = x

x = 100

This implies that when 85 chose outdoor, 100 chose indoor for boys;

Total = 100 + 85

Total = 185 boys surveyed

<em>Recall that the question says the same number of boys and girls were surveyed</em>

This implies that

Total Girls Surveyed = 185

For the girl ratio;

Outdoor to Indoor= 3:2

Number of girls that chose outdoor is as follows;

Outdoor = \frac{3}{3 + 2} * Total

Outdoor = \frac{3}{3 + 2} * 185

Outdoor = \frac{3}{5} * 185

Outdoor = \frac{555}{5}

Outdoor = 111

<em>Hence, the number of girls that chose outdoor is 111</em>

4 0
3 years ago
A bag contains 1 red, 1 yellow, 1 blue, and 1 green marble. What is the probability of choosing a green marble, not replacing it
lys-0071 [83]

The probability for choosing green and red is \frac{1}{12}

<u>Solution:</u>

Given that , A bag contains 1 red, 1 yellow, 1 blue, and 1 green marble.

We have to find what is the probability of choosing a green marble, not replacing it, and then choosing a red marble?

Now, we know that,

\text { probability of an event }=\frac{\text { number of favourable outcomes }}{\text { total number of outcomes }}

So, total possible outcomes = 1 red + 1 yellow + 1 blue + 1 green = 4

\text { Now, probability for green marble }=\frac{1 \text { green marble }}{4 \text { marbles }}=\frac{1}{4}

And now, total outcomes will be only 3 as we are not replacing the picked marble.

\begin{array}{l}{\text { Then, probability for red marble }=\frac{1 \text { red marble }}{3 \text { marbles }}=\frac{1}{3}} \\\\ {\text { Then overall probability }=\frac{1}{4} \times \frac{1}{3}=\frac{1}{12}}\end{array}

Hence, the probability for choosing green and red is \frac{1}{12}

6 0
3 years ago
Read 2 more answers
What is the solution to this system of equations ?
Vanyuwa [196]

Answer: x=2,y=6,z=−5

Step-by-step explanation:

7 0
3 years ago
The following graph represents the quadratic parent function.<br> TRUE OR FALSE
Alex17521 [72]

Answer:

True

Step-by-step explanation:

the graph makes a loop and both ends go in the same direction

3 0
3 years ago
Can someone please help me with this problem
alina1380 [7]
30 dollars per disk.
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