All categories

2 years ago

What is the domain if the function? Interval Notation.Thank you for the help!

Mathematics

1 answer:

kramer2 years ago

5 0

Interval notation:

−
∞
,
−
2
)
∪
(
−
2
,
2
)
∪
(
2
,
∞
)

Hope this help I haven’t done this in awhile

You might be interested in

Which of these things does not show that a reaction has occurred?

Rus_ich [418]

I believe it may be C. Because, the color changing has nothing to do with the reaction you get.

7 0

3 years ago

Read 2 more answers

I have almost like an out suffering with this one.please!help!

makkiz [27]

120 Fluid ounces in liters is 3.549 liters, so the answer is definitely A.

7 0

3 years ago

Read 2 more answers

3.Which value of x makes the equation 1.25(4x − 10) = 7.5 true?

In-s [12.5K]

Answer:

x=4

Step-by-step explanation:

1. distributive property

2. combine like terms

3. inverse operation

4. division or multiplication property

8 0

3 years ago

Read 2 more answers

SOME ONE HELP!!! You are still at (1,5). The zombie is 8.7 units below you. Enter the correct coordinates of the zombie below.

zaharov [31]

Answer:

(1,-3.7)

Step-by-step explanation:

subtract the y axis to go down

5 - 8.7 = -3.7

4 0

2 years ago

Read 2 more answers

Please help with this calculus problem!

ELEN [110]

$\dfrac{\mathrm dQ}{\mathrm dt}=\dfrac{a(1-5bt^2)}{(1+bt^2)^4}$
$Q(t)=\displaystyle\int\frac{a(1-5bt^2)}{(1+bt^2)^4}\,\mathrm dt$

Let $t=\dfrac1{\sqrt b}\tan u$ , so that $\mathrm dt=\dfrac1{\sqrt b}\sec^2u\,\mathrm du$ . Then the integral becomes

$\displaystyle\frac a{\sqrt b}\int\frac{1-5b\left(\frac1{\sqrt b}\tan u\right)^2}{\left(1+b\left(\frac1{\sqrtb}\tan u\right)^2\right)^4}\sec^2u\,\mathrm du$
$=\displaystyle\frac a{\sqrt b}\int\frac{1-5\tan^2u}{(1+\tan^2u)^4}\sec^2u\,\mathrm du$
$=\displaystyle\frac a{\sqrt b}\int\frac{1-5\tan^2u}{\sec^6u}\,\mathrm du$
$=\displaystyle\frac a{\sqrt b}\int(\cos^6u-5\sin^2u\cos^4u)\,\mathrm du$
$=\displaystyle\frac a{\sqrt b}\int(6\cos^2u-5)\cos^4u\,\mathrm du$

One way to proceed from here is to use the power reduction formula for cosine:

$\cos^{2n}x=\left(\dfrac{1+\cos2x}2\right)^n$

You'll end up with

$=\displaystyle\frac a{16\sqrt b}\int(5\cos2u+8\cos4u+3\cos6u)\,\mathrm du$
$=\displaystyle\frac a{16\sqrt b}\left(\frac52\sin2u+2\sin4u+\frac12\sin6u\right)+C$
$=\dfrac a{32\sqrt b}(5\sin2u+4\sin4u+\sin6u)+C$
$Q(t)=\dfrac{at}{(1+bt^2)^3}+C$

6 0

3 years ago

What is the domain if the function? Interval Notation.Thank you for the help!​

What is the domain if the function? Interval Notation.Thank you for the help!