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seraphim [82]
4 years ago
12

Define the term volt.

Physics
1 answer:
Mila [183]4 years ago
4 0
1 volt is the difference in potential that 1 coulomb of charge requires 1 joule of energy
in order to cross, or gives up 1 joule of energy in crossing, depending on the sign of the
charge and whether it climbs or falls through the 1 volt.

1 volt = 1 joule per coulomb
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A light wave from a star has a frequency of 6.67 * 100 Hz and a wavelength of 4.50 x 10 to the power of -7 m.
Juliette [100K]

Answer:

speed =wavelenght x frequency

v=4.5 x 10 to the -7 x 667=0.3 x 10 to the -4 m/s

speed= distance/time

time=distance/speed

t=4 x 10 to the 16/0.3 x 10 to the -4=13.33 x 10 to the 20 seconds

Explanation:

5 0
3 years ago
An air bag is used to safely decrease the
Natalija [7]
The answer is 1. 4 is incorrect because you can't really decrease the mass of the driver. 3 is incorrect because accelerating the driver would cause more damage than not. 2 is incorrect because decreasing the distance would only cause more damage. 1 is correct because by increasing the length of time the force acts on the driver helps reduce the speed of the driver and cause the drive to sustain less injuries. Hope that helps.
7 0
4 years ago
Four identical resistors have 12 ohm each. Find the equivalent resistance Req when : (a) all four of them are connected in serie
Elanso [62]

Answer:

(a): When the four resistors are connected in series the equivalent resistor value is Req= 48Ω

(b): when the four resistors are connected in parallel the equivalent resistor value is Req=3Ω

Explanation:

R=R1=R2=R3=R4= 12Ω

(a)

Req= R1+R2+R3+R4

Req= 48 Ω

(b)

Req= (1/12 * 4)⁻¹

Req= 3 Ω

6 0
3 years ago
A 480N sphere 40.0cm in radius rolls without slipping 1200cm down a ramp that is inclined at 53 0 with the horizontal. What is t
IgorC [24]

As we know that sphere roll without slipping so there is no loss of energy in this case

so here we can say that total energy is conserved

Initial Kinetic energy + initial potential energy = final kinetic energy + final potential energy

\frac{1}{2}mv_i^2 + mgh = \frac{1}{2}mv^2 + \frac{1}{2}I\omega^2+ mgh'

as we know that ball start from rest

v_i = 0

height of the ball initially is given as

h = Lsin\theta

h = 1200sin53 = 960 cm

also we know that

I = \frac{2}{5}mR^2

also for pure rolling

v = r\omega

also we know that

480 = m*9.8

m = 49 kg

now plug in all data in above equation

480*9.60 + 0 = \frac{1}{2}*49*(0.40*\omega)^2 + \frac{1}{2}*\frac{2}{5}*49*(0.40)^2\omega^2 + 0

4608 = 3.92\omega^2 + 1.568\omega^2

\omega^2 = 839.65

\omega = 29 rad/s

So speed at the bottom of the inclined plane will be 29 rad/s

7 0
4 years ago
You kick a soccer ball of mass 0.41 kg. the ball leaves your foot with an initial speed of 23 m/s. (a what is the magnitude of t
svetoff [14.1K]
Impulse describes the change of momentum. Since we don't know the momentum of the soccer ball before the hit, this question is hard to answer. If you assume the momentum of the ball before the hit was p = 0, then the change in momentum is just Δp = Impulse = mv.
7 0
3 years ago
Read 2 more answers
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